The conversations need to solve this problem:
1 cal = 4.184 joules
1 Kcal= 1000 calories
1 kj= 1000 joules
or a more direct approach---->> 1 Kcal = 4.184 Kjoules
8.4 kcal (1000 calories/ 1 Kcal) x (4.184 joules/ 1 cal) x (1 Kj/ 1000 joules)= 35.1 Kj
or 8.4 kcal (4.184 Kj/ 1 kcal)= 35.1 Kj (same answer)
Answer:
The net charge on each lysine molecule would be -1.
Explanation:
- <u>When the pH is above 2.2</u> the deprotonated form of the carboxylic acid is more present, while the amino group and side chain (which is also amino) remain protonated (with a positive charge):
R-COOH ↔ R-COO⁻
R-NH₃⁺
R'-NH₃⁺
Net charge = +1
- <u>When pH is above 9.0</u>, the carboxyl group remains deprotonated, while the amino group is deprotonated and the side chain is protonated:
R-COOH ↔ R-COO⁻
R-NH₂
R'-NH₃⁺
Net charge = 0
- <u>When pH is above 10.5</u>, the carboxyl group remains deprotonated, while both the amino group and the side chain are deprotonated:
R-COOH ↔ R-COO⁻
R-NH₂
R'-NH₂
Net charge = -1
So at pH=13 (which is above 10.5) the net charge is -1.
N2(g) + 3H2(g) =2NH3(g)
Number of moles of reactants > product...
Therfore if pressure is increased.
Equilibrium is disturbed according to LCP....
Equilibrium shift to the right (product)
......
If you want to understant the fundamental concept:
Take for example 2A + 3B = 4C
Reactant: 5 moles (5 volumes)
Product: 4 moles (4 volumes)
When pressure of a gas is increased, volume decreases!
(Vice-versa)
If pressure is increased, volume decreases. Hence number of collisions INCREASES(constrain). Equilibrium shifts in such a direction so as to decrease the number of collision accordinf to LCP...
This happens when number of paeticles decreases as equilibrium shift forward because the forward reaction is accompanied by a decrease in number of particles (5 to 4)
