All categories

3 years ago

Hydrogen chloride and oxygen react to form chlorine and water, like this:

Chemistry

2 answers:

leva [86]3 years ago

8 0

Answer:

Kp = (Partial pressure H₂O) . (Partial Pressure Cl₂)² / Partial pressure O₂ . (Partial Pressure HCl)⁴

Explanation:

This is the reaction:

4 HCl (g) + O₂ (g) ⇒ 2 Cl₂ (g) + 2 H₂O(g)

Kp = (Partial pressure H₂O) . (Partial Pressure Cl₂)² / Partial pressure O₂ . (Partial Pressure HCl)⁴

goldenfox [79]3 years ago

6 0

Answer:

Kp = ((pH2O)²*(pCl2)²] /((pO2)(pHCl)^4)

Explanation:

Step 1: data given

Hydrogen chloride = HCl

oxygen = O2

chlorine = Cl2

water = H2O

Step 2: The balanced equation

4 HCl(g)+O2(g) ⇒ 2 Cl2(g)+2 H20(g)

Step 3: Define the pressure equilibrium constant

Kc = [[H2O]²*[Cl2]²] /[[O2][HCl]^4]

Kp = ((pH2O)²*(pCl2)²] /((pO2)(pHCl)^4)

⇒ with pH2O = the partial pressure of H2O

⇒ with pCl2 = the partial pressure of Cl2

⇒ with pO2 = the partial pressure of O2

⇒ with pHCl = the partial pressure of HCl

You might be interested in

What does the symbol H stand for

muminat

Answer:

enthalpy

Explanation:

If it is used with a triangle in front, (delta H), that means the change in enthalpy. Delta H= (m)(s)(Delta T). m=mass of products, s=heat of the products, Delta T = change in temperature.

Hope that helps

4 0

3 years ago

Bf3 can be octet or not

makvit [3.9K]

Answer:

(BH3 follows the octet rule by dimerizing, as Hadi Kurniawan AR pointed out.) For H and He, an "octet" = 2 electrons. Boron does prefer to follow the octet rule, in that it likes to form borate compounds such as NaBH4. It also is happy to form compounds with elements with lone pairs.

7 0

2 years ago

When 8.0 moles of methanol are reacted with 9.0 moles of oxygen, how many moles of water vapor does the reaction produce?

nadya68 [22]

Answer:

12 moles of H₂O are formed in this combustion.

Explanation:

First of all, think the reaction:

2CH₃OH (l) + 3O₂ (g) → 2CO₂ (g) + 4H₂O (g)

Ratio in the reactants is 2:3, so 2 mol of methanol need 3 mol of oxygen to react. Then 8 mol of CH₃OH, will need (8.3)/2 = 12 moles of O₂

We have 9 moles of O₂, so this is the limiting reactant.

3 mol of oxygen produce 4 mol of water