1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ELEN [110]
3 years ago
8

Is vinegar in water a true solution, suspension or colloid

Chemistry
1 answer:
nata0808 [166]3 years ago
4 0

Answer:

Solution

Explanation:

Solution

You might be interested in
Would you expect Nio to dissolve in an aqueous solution of NaNO3?
Doss [256]

Answer:

NiO Does Not Dissolve In An Aqueous Solution Of NaNO3.

Explanation:

6 0
3 years ago
Definition: This is a change in velocity per time.
ladessa [460]

Answer: acceleration

a = 5.36 m/s²

Explanation: solution attached:

Convert first 60 mi/h to m/s

Use the formula for acceleration

a = vf - vi /t

8 0
3 years ago
Combustion reactions are exothermic. The heat of reaction for the combustion of 2-methylheptane, C8H18, is 1.306×103 kcal/mol. W
WARRIOR [948]

Answer:

11.45kcal/g

2.612 × 10³ kcal

Explanation:

When a compound burns (combustion) it produces carbon dioxide and water. The combustion of 2-methylheptane can be represented by the following balanced equation:

2 C₈H₁₈ + 25 O₂ ⇄ 16 CO₂ + 18 H₂O

It releases  1.306 × 10³ kcal every 1 mol of C₈H₁₈ that is burned.

<em>What is the heat of combustion for 2-methylheptane in kcal/gram?</em>

We know that the molar mass of C₈H₁₈ is 114.0g/mol. Then, using proportions:

\frac{1.306 \times 10^{3}Kcal}{1mol} .\frac{1mol}{114.0g} =11.45kcal/g

<em>How much heat will be given off if molar quantities of 2-methylheptane react according to the following equation? 2 C₈H₁₈ + 25 O₂ ⇄ 16 CO₂ + 18 H₂O</em>

In this equation we have 2 moles of C₈H₁₈. So,

2mol \times\frac{1.306 \times 10^{3}kcal }{1mol} =2.612\times 10^{3}kcal

3 0
3 years ago
C2h6 what is the name
My name is Ann [436]
Ethane
see the picture for explanation

8 0
3 years ago
If you have a 1.0 L buffer containing 0.208 M NaHSO3 and 0.134 M Na2SO3, what is the pH of the solution after addition of 50.0 m
Vlada [557]

Answer:

pH = 7.233

Explanation:

Initially, the buffer contains 0.208 moles of NaHSO₃ and 0.134 moles of Na₂SO₃.

NaHSO₃ reacts with NaOH thus:

NaHSO₃ + NaOH → Na₂SO₃ + H₂O

50.0 mL of 1.00 M NaOH are:

0.0500L × (1mol / 1L) = 0.0500moles of NaOH added. That means after the addition are produced  0.0500moles of Na₂SO₃ and consumed 0.0500moles of NaHSO₃. That means final moles of the buffer are:

NaHSO₃: 0.208 mol - 0.050 mol = <em>0.158 mol</em>

Na₂SO₃: 0.134 mol + 0.050 mol = <em>0.184 mol</em>

<em> </em>

As pKa of this buffer is 7.167, it is possible to use H-H equation to find pH, thus:

pH = pKa + log₁₀ [Na₂SO₃] / [NaHSO₃]

pH = 7.167 + log₁₀ [0.184] / [0.158]

<em>pH = 7.233</em>

6 0
3 years ago
Other questions:
  • A gas is contained in a thick-walled balloon. When the pressure changes from 45.0 bar to 96.0 bar, the volume changes from 1.20
    14·2 answers
  • For the reaction CO2(g) + H2(g)CO(g) + H20(g)
    13·1 answer
  • Write the electron configuration when Sulfur gains two electrons
    10·1 answer
  • What characterizes a Homo genesis mixture
    8·1 answer
  • Used oil needs to be kept in what kind of containers
    9·1 answer
  • Liquid 1 has a density of 2.0 g/ml, Liquid 2
    10·1 answer
  • Calculate the number of joules needed to change the temperature of 40.0 g of water from 33.0 degree c to 43.0 degree c
    7·1 answer
  • Carbonic acid weathering limestone <br><br> a<br> Chemical Change<br> b<br> Physical Change
    7·1 answer
  • If I have a cube with a mass of 24g and a volume of 6cm3, what will be the density of the cube?
    13·1 answer
  • In an electroplating apparatus, where does the reduction reaction occur?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!