A neutral atom must have the same number of neutrons and electrons true or false

To arrive at the number of hydrogen atoms, What can be said about the relationship between the number of hydrogen atoms and the

Semenov [28]

Answer:

nothing shsheysyeggehssl

6 0

3 years ago

explain how a metal with one valence electron compares with a metal with more than one valence electron

slamgirl [31]

Explanation:

A metal with one valence electron is highly reactive compared to those with more than one electron.

Atoms including those of metals reacts in order attain a stable electronic configuration just like those of noble gases.

An atom with one valence electron have just one electron in its valence shell.

Metals generally have large sizes.
when the electron in this shell is lost, the metal atom can then attain stability.
therefore, such atom will quickly want to combine with any other willing to accept the electron so that they can be stable.
Those with more than one electron will find it difficult to lose them.
It requires huge energy to remove such electrons compared to the ones with only one valence electron.

learn more:

Valence electrons brainly.com/question/3023499

#learnwithBrainly

7 0

3 years ago

Metals can be highly purified using electrolysis. Which equation best reflects the overall process of purifying copper?

makvit [3.9K]

Answer:

A. Cu^+2(aq)cathode ---> Cu^+2(aq)anode

Explanation:

Electrolysis is the process in which current is passed through a solution thereby causing a chemical change at the anode and cathode. Copper is being purified using electrolysis by using impure copper at the anode and pure copper at the cathode. This pure and impure copper are placed in a copper(ii)sulfate electrolyte solution and dc current is made to pass through it. The resulting changes at the anode and cathode are given by the equation:

cathode: Cu²⁺ + 2e⁻ ⇒ Cu

anode: Cu ⇒ Cu²⁺ + 2e⁻

3 0

4 years ago

Read 2 more answers

A nail contains 0.10 moles of iron. How many grams of iron are in the nail?

oksano4ka [1.4K]

Answer:

10.8

Explanation:

That's my guess, I hope you figure everything out though.

4 0

3 years ago

At 25°C, K = 0.090 for the following reaction. H2O(g) + Cl2O(g) equilibrium reaction arrow 2 HOCl(g) Calculate the concentration

wlad13 [49]

Answer:

[HOCl] = 0.00909 mol/liter

[H₂O] = 0.03901 mol/liter

[Cl₂O] = 0.02351 mol/liter

Explanation:

1. Chemical reaction:

$H_2O(g)+Cl_2O(g)\rightleftharpoons 2 HOCl(g)$

2. Initial concentrations:

i) 1.3 g H₂O

Number of moles = 1.3g / (18.015g/mol) = 0.07216 mol

Molarity, M = 0.07216 mol / 1.5 liter = 0.0481 mol/liter

ii) 2.2 g Cl₂O

Number of moles = 2.2 g/ (67.45 g/mol) = 0.0326 mol

Molarity = 0.0326mol / 1.5 liter = 0.0217 mol/liter

3. ICE (Initial, Change, Equilibrium) table

$H_2O(g)+Cl_2O(g)\rightleftharpoons 2 HOCl(g)$

I 0.0481 0.0326 0

C -x -x +x

E 0.0481-x 0.0326-x x

4. Equilibrium expression

$K_c=\dfrac{[HOCl]^2}{[H_2O].[Cl_2O]}$

$0.09=\dfrac{x^2}{(0.0481-x)(0.0326-x)}$

5. Solve:

$x^2=0.09(x-0.0481)(x-0.0326)\\\\0.91x^2+0.007263x-0.000141125=0$

Use the quadatic formula:

$x=\dfrac{-0.007263\pm \sqrt{(0.007263)^2-4(0.91)(-0.000141125)}}{2(0.91)}$

The positive result is x = 0.00909

Thus the concentrations are:

[HOCl] = 0.00909 mol/liter

[H₂O] = 0.0481 - 0.00909 = 0.03901 mol/liter

[Cl₂O] = 0.0326 - 0.00909 = 0.02351 mol/liter

3 0

3 years ago