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NikAS [45]
3 years ago
10

Someone please do a True or false of all of these

Chemistry
1 answer:
GuDViN [60]3 years ago
8 0

Answer:

1. False

2. True

3. False

4. False

5. True

6. False

7. True

8. True

9. True

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Calculate the amount in grams of Na2CO3 needed in a reaction with HCl to produce 120g NaCl?
klemol [59]
The balanced chemical reaction is written as :

Na2CO3<span> + 2HCl === 2NaCl + H2O + CO2
</span>
We are given the amount of NaCl to be produced from the reaction. This will be the starting point for the calculations. We do as follows:

120 g NaCl ( 1 mol / 58.44 g) ( 1 mol Na2CO3 / 2 mol NaCl)( 105.99 g / 1 mol ) = 1108.82 g Na2CO3 needed
8 0
3 years ago
What is chemistry? ​
kirill [66]

Answer:the branch of science which examines the material of the universe and changes that these materials undergo

Chemistry deals with composition,structure,properties of matter and changes that these materials undergo

3 0
3 years ago
The reaction for the decomposition of ammonia (NH3) can be written as shown. If a student starts with 21.7 g of ammonia, how man
Eddi Din [679]
3.88 grams will be released I believe
3 0
4 years ago
Read 2 more answers
A 1.250-g sample of benzoic acid, C7H6O2, was placed in a combustion bomb. The bomb was filled with an excess of oxygen at high
Degger [83]

Answer:

3224 kJ/mol

Explanation:

The combustion of benzoic acid occurs as follows:

C₇H₆O₂ + 13/2O₂ → 7CO₂ + 3H₂O + dE

The change in temperature in the reaction is the change due the energy released, that is:

3.256K * (10.134kJ / K) = 33.00kJ are released when 1.250g reacts

To find the heat released per mole we have to find the moles of benzoic acid:

<em>Moles benzoic acid -Molar mass: 122.12g/mol-:</em>

1.250g * (1mol / 122.12g) = 0.0102 moles

<em />

The dE combustion per mole of benzoic acid is:

33.00kJ / 0.0102moles =

<em>3224 kJ/mol </em>

4 0
3 years ago
What volume of 18.0 m sulfuric acid is required to prepare 16.5 l of 0.126 m h2so4?
Blababa [14]

this is a dilution question where a certain volume is taken from a more concentrated solution and diluted to make a solution with a lower concentration.

the dilution forumla is as follows

c1v1 = c2v2

where c1 is concentration and v1 is volume of the more concetrated solution

c2 is concentration and v2 is volume of the diluted solution

substituting the values in the equation

18.0 M x V = 0.126 M x 16.5 L

V = 0.1155 L

volume of 115.5 mL is taken from the 18.0 M solution and diluted upto 16.5 L solution.

6 0
4 years ago
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