Answer:
18/24 for the first one
Step-by-step explanation:
Answer:
d. 9 integers
Step-by-step explanation:
Given that two numbers are said to be 'relatively prime' if their greatest common factor is 1.
We are to find relatively prime with 28 which are greater than 10 and less than 30
We have 11,12,13...29 satisfying the criteria greater than 10 and less than 30
To be relatively prime with 28, common factors should be only 1.
28 = 2x2x 7. Hence the numbers which do not have factors as 2 or 7 will be relatively prime. Remove all the even numbers from the list.
We have 11,13,15....29.
Of these 21 is the multiple of 7 so remove that.
Thus we have now 11,13,15,17,19,23,25,27,29
9 integers
d. 9 integers
Answer:Missing: 3y² Бу
Step-by-step explanation:
Answer:
45
Step-by-step explanation:
9, 13, 17, 21, 25
We are adding 4 each time
9+4 = 13
13+4 =17
17+4 = 21
The common difference =4
a1 = 9
The formula is
an = a1+d(n-1) where n is the term number
an = 9+4(n-1)
We want the 10th term
a10 = 9+4(10-1)
= 9+4(9)
= 9+36
= 45
Answer:
Step-by-step explanation:
x+y=a
a=x+y
x−y=b
b=x−y
Good luck honey!