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ohaa [14]
3 years ago
6

3. Suppose you are testing H0 : µ = 20 vs H1 : µ > 20. The sample is large (n = 71) and the variance, σ 2 , is known. (a) Fin

d the critical value(s) corresponding to α = 0.08. (b) You find that z = 1.56. Based on your critical value, what decision do you make regarding the null hypothesis (i.e. do you Reject H0 or Do Not Reject H0)?
Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
7 0

Answer:

We reject the null hypothesis.

Step-by-step explanation:

We are given the following information in the question:

Sample size, n = 71

Population variance is known.

Level of significance, α = 0.08

z_{\text{stat}} = 1.56

The null and alternate hypothesis are:

H_{0}: \mu = 20\\H_A: \mu > 20

We use one-tailed z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} } = 1.56

Now, z_{critical} \text{ at 0.08 level of significance } = 1.41

Since,  

z_{stat} > z_{critical}

We fail to accept the null hypothesis and reject it and accept the alternate hypothesis.

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Juliana made one container of berry punch and served it to her friends at a picnic. The container served 8 people. What would be
LiRa [457]

Answer:64 ounces

Step-by-step explanation:

average is 8 ounces per serving

8 0
3 years ago
For <img src="https://tex.z-dn.net/?f=e%5E%7B-x%5E2%2F2%7D" id="TexFormula1" title="e^{-x^2/2}" alt="e^{-x^2/2}" align="absmiddl
nevsk [136]
I'm assuming you're talking about the indefinite integral

\displaystyle\int e^{-x^2/2}\,\mathrm dx

and that your question is whether the substitution u=\dfrac x{\sqrt2} would work. Well, let's check it out:

u=\dfrac x{\sqrt2}\implies\mathrm du=\dfrac{\mathrm dx}{\sqrt2}
\implies\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt2\int e^{-(\sqrt2\,u)^2/2}\,\mathrm du
=\displaystyle\sqrt2\int e^{-u^2}\,\mathrm du

which essentially brings us to back to where we started. (The substitution only served to remove the scale factor in the exponent.)

What if we tried u=\sqrt t next? Then \mathrm du=\dfrac{\mathrm dt}{2\sqrt t}, giving

=\displaystyle\frac1{\sqrt2}\int \frac{e^{-(\sqrt t)^2}}{\sqrt t}\,\mathrm dt=\frac1{\sqrt2}\int\frac{e^{-t}}{\sqrt t}\,\mathrm dt

Next you may be tempted to try to integrate this by parts, but that will get you nowhere.

So how to deal with this integral? The answer lies in what's called the "error function" defined as

\mathrm{erf}(x)=\displaystyle\frac2{\sqrt\pi}\int_0^xe^{-t^2}\,\mathrm dt

By the fundamental theorem of calculus, taking the derivative of both sides yields

\dfrac{\mathrm d}{\mathrm dx}\mathrm{erf}(x)=\dfrac2{\sqrt\pi}e^{-x^2}

and so the antiderivative would be

\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt{\frac\pi2}\mathrm{erf}\left(\frac x{\sqrt2}\right)

The takeaway here is that a new function (i.e. not some combination of simpler functions like regular exponential, logarithmic, periodic, or polynomial functions) is needed to capture the antiderivative.
3 0
3 years ago
Cynthia Bech want to buy a rug for a room that i 20 ft wide and ft long. She want to leave a uniform trip of 29 floor around the
Hoochie [10]

On solving the question, we got that - The dimensions of the rug should be 18 feet and 24 feet

<h3>What is area of rectangle?</h3>

By multiplying the rectangle's length by its breadth, we may get its area.

Equiangular quadrilaterals, like rectangles, are known in this way. This is so because a rectangle is a four-sided quadrilateral shape with parallel sides that are equal to one another and four corners with 90o angles. Rectangles are sometimes known as equiangular quadrilaterals since all of its angles are 90 degrees.

the parameters provided;

The room is 20 feet by 26 feet in size.

432 feet2 is the largest area rug she can afford.

If the floor will be a uniform stripe around the rug, then each dimension should have its uniform extra length of floor =  (y).

Area = Length X Width\\432 = ((20=y) X (26-y)\\432 = 520 - 20y - 26y + y^2\\y^2 - 46y+88=0\\

here, a= 1, b= -46, c =88

y = \frac{-b +/- \sqrt{b^2 - 4ac} }{2a} \\\\

y = \frac{-(-46) +/- \sqrt{(-46)^2 - 4X1X88} } {2} \\\\y = 44 \\or\\ y =  2

Therefore, Length = 20-2 = 18 ft

and width = 26-2 = 24ft

To know more about rectangle visit:

brainly.com/question/15019502

#SPJ4

8 0
1 year ago
HELP PLEASE I REALLY SUCK AT MATH
siniylev [52]

Answer:

D is the answer because 4 goes into all of them.

3 0
2 years ago
Can someone help me with this
GREYUIT [131]

Answer:

2 5/5 is the anwser

Step-by-step explanation:

5 0
2 years ago
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