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anygoal [31]
2 years ago
8

Old-fashioned pendulum clocks are powered by masses that need to be wound back to the top of the clock about once a week to coun

teract energy lost due to friction and to the chimes. One particular clock has three masses: 4.0 kg, 4.0 kg, and 6.0 kg. They can drop 1.3 meters. How much energy does the clock use in a week?
Physics
1 answer:
Andreyy892 years ago
6 0

Answer:

Energy, E = 178.36 J

Explanation:

It is given that,

Mass 1, m_1=4\ kg

Mass 2, m_2=4\ kg

Mass 3, m_3=6\ kg

Height from which they are dropped, h = 1.3 m

Let m is the energy used by the clock in a week. The energy is equal to the gravitational potential energy. It is given by :

E=(m_1+m_2+m_3)gh

E=(4+4+6)\times 9.8\times 1.3

E = 178.36 J

So, the energy used by the clock in a week is 178.36 Joules. Hence, this is the required solution.

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What is the strength of the electric field in a region where the electric potential is constant?
Roman55 [17]

Answer:

Where the electric potential is constant, the strength of the electric field is zero.

Explanation:

As a test charge moves in a given direction, the rate of change of the electric potential of the charge gives the potential gradient whose negative value is the same as the value of the electric field. In other words, the negative of the slope or gradient of electric potential (V) in a direction, say x, gives the electric field (Eₓ) in that direction. i.e

Eₓ = - dV / dx        ----------(i)

From equation (i) above, if electric potential (V) is constant, then the differential (which is the electric field) gives zero.

<em>Therefore, a constant electric potential means that electric field is zero.</em>

4 0
3 years ago
Calculate the force on an object with mass of 50kg and gravity of 10​
GarryVolchara [31]
Answer: 500 N

Explanation:

The formula to find the force exerted by a mass, we may use F = mg, where g, the gravity, and a, the acceleration, can be interchangeable in the formula.

1) F = 50 x 10
2) F = 500 N

Hope this helps, brainliest would be appreciated :)
6 0
3 years ago
STATE THE LAWS OF CONSERVATION OF MOMENTUM​
dalvyx [7]

\Huge  \mid   \underline {\mathcal {{{\color{purple}{Answer...}}}}} \mid

When two bodies collide with each other in the absence of an external force, then the total final momentum of the bodies is equal to their total initial momentum.

6 0
3 years ago
The value of acceleration due to gravity (g) on Pluto is about . 0.61 meters/second2. How much will an object that weighs 250 ne
Annette [7]
First, determine the mass of the object by dividing its weight on Earth by 9.8 m/s² as shown below,
                                   m = 250 N / 9.8 m/s² = 25.51 kg
Then, multiply the obtained mass by the acceleration due to gravity (g) on Pluto. 
                                  W (in Pluto) = (25.51 kg) x (0.61 m/s²)  = 15.56 N
Therefore, the object will only weigh 15.56 N. 
8 0
3 years ago
Light of wavelength 623.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 76.5 cm from the slit.
Dvinal [7]

Answer:

Explanation:

wave length of light λ = 623 x 10⁻⁹ m .

Distance of screen D = 76.5 x 10⁻² m

width of slit        =      d

Distance on the screen between the second order minimum and the central maximum       =  2  λ D / d

1.11 x 10⁻²  = (2 x 623 x 10⁻⁹ x 76.5 x 10⁻² )/ d

d =  ( 2 x 623 x 10⁻⁹ x 76.5 x 10⁻²) / 1.11 x 10⁻²

= 85872.97 x  10⁻⁹

=  85.87297 x  10⁻⁶

= 85.87 μm

width a of the slit is = 85.87 μm

6 0
3 years ago
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