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anygoal [31]
2 years ago
8

Old-fashioned pendulum clocks are powered by masses that need to be wound back to the top of the clock about once a week to coun

teract energy lost due to friction and to the chimes. One particular clock has three masses: 4.0 kg, 4.0 kg, and 6.0 kg. They can drop 1.3 meters. How much energy does the clock use in a week?
Physics
1 answer:
Andreyy892 years ago
6 0

Answer:

Energy, E = 178.36 J

Explanation:

It is given that,

Mass 1, m_1=4\ kg

Mass 2, m_2=4\ kg

Mass 3, m_3=6\ kg

Height from which they are dropped, h = 1.3 m

Let m is the energy used by the clock in a week. The energy is equal to the gravitational potential energy. It is given by :

E=(m_1+m_2+m_3)gh

E=(4+4+6)\times 9.8\times 1.3

E = 178.36 J

So, the energy used by the clock in a week is 178.36 Joules. Hence, this is the required solution.

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For two objects with masses 100 kg and 500 kg to be 20 meters apart , find the gravity between them
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Answer:

8,3375*10^-9 N

Explanation:

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Starting from rest, a solid sphere rolls without slipping down an incline plane. At the bottom of the incline, what does the ang
Marrrta [24]

Answer:

2/R*sqrt (g*s*sin(θ)) = w

Explanation:

Assume:

- The cylinder with mass m

- The radius of cylinder R

- Distance traveled down the slope is s

- The angular speed at bottom of slope w

- The slope of the plane θ

- Frictionless surface.

Solution:

- Using energy principle at top and bottom of the slope. The exchange of gravitational potential energy at height h, and kinetic energy at the bottom of slope.

                                         ΔPE = ΔKE

- The change in gravitational potential energy is given as m*g*h.

- The kinetic energy of the cylinder at the bottom is given as rotational motion: 0.5*I*w^2

- Where I is the moment of inertia of the cylinder I = 0.5*m*R^2

We have:

                              m*g*s*sin(θ) = 0.25*m*R^2*w^2

                              2/R*sqrt (g*s*sin(θ)) = w

- The angular velocity depends on plane geometry θ , distance travelled down slope s, Radius of the cylinder R , and gravitational acceleration g

3 0
3 years ago
The infant's tendency to turn its head toward things that touch its cheek is known as the
katovenus [111]

Answer:

I think it is <em><u>Rooting</u></em><em> </em><u><em>Reflex</em></u>

4 0
3 years ago
Read 2 more answers
Which is a component of pseudoscience, but not science?
quester [9]

Answer:

The statements, observations, beliefs and suppositions all are the components of the pseudoscience.

Explanation:

The claims included in the pseudoscience including the beliefs, statements and practices are claimed to be scientific but these are devoid of any scientific evidences provided by the experimental procedures.

5 0
3 years ago
n an experiment of a simple pendulum, measurements show that the pendulum has length m, mass kg, and period s. Take m/s2 . i. Us
barxatty [35]

Answer:

The answer is "(1.265 \pm 0.010) \ s \ and \ 0.709 \%"

Explanation:

In point i:

T_{theo}= 2\pi \sqrt{\frac{l}{g}}

        =2\pi\sqrt{\frac{0.397}{9.8}}\\\\= 1.265 \ s

If  error in the theoretical time period :

\frac{\Delta T_{theo}}{T_theo} = \frac{1}{2}  \frac{\Delta l }{l}\\\\\Delta T_{theo} = 1.265 \times \frac{1}{2} \times \frac{0.006}{0.397}

           = 0.010 \ s

 T_{theo} = (1.265 \pm 0.010) \ s

In point ii:

\% \ difference = \frac{|T_{exp} -T_{theo}|}{\frac{T_{exp}+T_{theo}}{2}} \times 100

<h3>                     = \frac{1.274 -1.265}{\frac{1.274+1.265}{2}} \times 100\\\\=0.709 \%</h3>
5 0
2 years ago
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