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Cloud [144]
3 years ago
15

How do magnets loose their magnetism when stored without keepers​

Physics
1 answer:
Daniel [21]3 years ago
8 0

Answer:

Storing it at a temperature greater than its Curie temperature will demagnetize it. The Curie temperature--named after the French scientist Pierre Curie--is the temperature at which magnets lose their permanent magnetism. ... Samarium cobalt, neodymium, and ceramic/ferrite magnets are brittle.

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The main reason for making the cover of a vacuum
prohojiy [21]

Answer:

(A) conduction

Explanation:

parts of that are touching other parts and thus create heat!!!! dont lose that heat!

7 0
3 years ago
How does the law of the conservation of mass relate to "You can't get something for nothing
ivolga24 [154]
You can't get something from nothing is practically stating the law. The law means states that energy can't be created or destroyed, in other words, it's constant. So in saying so, you truly can't get something from nothing
8 0
3 years ago
A fission reaction is one in which the weaker electrostatic repulsion force wins out over the ___________ nuclear force and, as
goblinko [34]
The strong nuclear force is responsible for holding nuclei together
8 0
3 years ago
Read 2 more answers
A 62.0 kg sprinter starts a race with an acceleration of 1.44 m/s2. If the sprinter accelerates at that rate for 30 m, and then
Dominik [7]

Answer:

The time taken for the race is 17.20 s.

Explanation:

It is given in the problem that a 62.0 kg sprinter starts a race with an acceleration of 1.44 meter per second square.The initial speed of the sprinter is zero as it starts from the rest.

Calculate the final speed of the sprinter.

The expression for the equation of the motion is as follows;

v^{2}-u^{2}= 2as

Here, u is the initial speed, v is the final speed, a is the acceleration and s is the distance.

Put u= 0, s=30 m and a= 1.44 ms^{-2}.

v^{2}-(0)^{2}= 2(1.44)(30)

v= 9.3 m^{-1}

Calculate time taken to cover 30 m distance.

The expression for the equation of motion is as follows;

s=ut+\frac{(1)}{2}at^2

Put u= 0, s=30 m and a= 1.44 ms^{-2}.

30=(0)t+\frac{(1)}{2}(1.44)t^2

t=6.45 s

Calculate the time taken to complete his race.

T= t+t'

Here, t is the time taken to cover 30 m distance and t' is the time taken to cover 100 m distance.

T=6.45+\frac{s'}{v}

Put s= 30 m, v= 9.3 m^{-1} and s'= 100 m.

T=6.45+\frac{(100)}{9.3}

T= 17.20 s

Therefore, the time taken for the race is 17.20 s.

6 0
3 years ago
A runner whose mass is 54 kg accelerates from a stop to a speed of 7 m/s in 3 seconds. (A good sprinter can run 100 meters in ab
Darya [45]

Answer:

a. F=126N

b. E_K=1323J

Explanation:

Given:

m=54kg

v=7 m/s

t= 3s

The runner force average to find given the equations

a.

F=m*a

a=\frac{v}{t}

F=m*\frac{v}{t}=54kg*\frac{7m/s}{3s}

F=126N

b.

Work done by the system by this force so

W=F*d

W=E_K

E_K=\frac{1}{2}*m*v^2

E_K=\frac{1}{2}*54kg*(7m/s)^2

E_K=1323J

6 0
3 years ago
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