<span>There is a net force of 15 N allowing Levi and Clara to move the box would be your answer which is B</span>
Complete Question
The complete question is shown on the first uploaded image
Answer:
The workdone is 
Explanation:
From the question we are told that
The initial Volume is 
The final volume is 
The external pressure is
Generally the change in volume is

Substituting values we have


Generally workdone is mathematically represented as

W is negative because the working is done on the environment by the system which is indicated by volume increase
Substituting values


Now 
Therefore 

Answer:
there should some picture to identify right?
pls edit your question and insert the picture..
Answer:
Plzzzzzzzzzzzzzzzz brainliest
Explanation:
In static friction, the frictional force resists force that is applied to an object, and the object remains at rest until the force of static friction is overcome. In kinetic friction, the frictional force resists the motion of an object. ... The frictional force itself is directed oppositely to the motion of the object.
Answer:
-0.79 J
Explanation:
We are given that





We have to find the work done by the electric force on the moving point charge.


Work done,
Where 
Using the formula

