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3 years ago

What do signal trainees do

Physics

1 answer:

Evgen [1.6K]3 years ago

8 0

Answer:

A signal apprentice works for a rail company, learning the duties of a signal maintainer through on-the-job training and experience. As part of this apprenticeship, you work on a railway to assist a seasoned signal maintainer as they install, repair, inspect, and test signal equipment.

Explanation:

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What must be true about two objects for conduction to take place? The objects must be different temperatures and they must be in

tia_tia [17]

Answer:

A.The objects must be different temperatures and they must be in contact.

Explanation:

5 0

3 years ago

Read 2 more answers

Starting from rest, a 2.1x10^-4 kg flea springs straight upward. While the flea is pushing off from the ground, the ground exert

Rainbow [258]

Answer:

a) The flea's speed when it leaves the ground is $v=1.88m/s$

b) The flea move $18cm$ upward while it is pushing off

Explanation:

<u>Knwons</u>

Mass $m=2.1\times 10^{-4} kg$ , Work $W=3.7\times 10^{-4} J$ and Force $F=0.41N$

a) Here we are going to use $W=\frac{1}{2} mv^{2}$ , so $v=\sqrt{\frac{2W}{m} }= \sqrt{\frac{2(3.7\times 10^{-4} J)}{2.1\times 10^{-4} kg} }=1.88m/s$

a) Here we are going to use $W=mgh$ , so $h=\frac{W}{mg}= \frac{3.7\times 10^{-4} J}{(2.1\times 10^{-4} kg)(9.8m/s^{2})} =0,1797m$ or $18cm$ approx.

7 0

3 years ago

What is the value of the angle of inclination of the slide?

ruslelena [56]

Answer:

63°

that's my answer

but then I am sorry if I'm wrong

Explanation:

90-27 = 63°

7 0

3 years ago

An oil drop with a mass of 8.3 grams and a charge of + 2.2 mC is floating 7.68 meters above a positively charged floor. What is

Alina [70]

Answer:

Correct answer: Q = 0.247 μC

Explanation:

Since the oil drop floats, this means that the weight of the drop and the Coulomb force are equal.

F = m · g drop's weight

Fc = k q Q / r² Coulomb force

where it was given:

k = 9 · 10⁹ N m²/C² dielectric constant,

q = 2.2 mC = 2.2 · 10⁻³ C drop's charge,

Q - floor's charge,

r = 7.68 m distance between drop and floor

m = 8.3 grams = 8.3 · 10⁻³ kg drop's weight

and g = 10 m/s²

F = Fc ⇒ k q Q / r² = m · g ⇒ Q = m · g · r²/ k · q

Q = 8.3 · 10⁻³ · 10 · 7.68² / 9 · 10⁹ · 2.2 · 10⁻³

Q = 24.72 · 10⁻⁸ C = 0.2472 · 10⁻⁶ C = 0.2472 μC

Q = 0.247 μC

God is with you!!!

8 0

3 years ago

In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 71.5 m/s. Th

lisabon 2012 [21]

Answer:

957.4845 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-71.5^2}{2\times 250}\\\Rightarrow a=-10.2245\ m/s^2$

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-71.5}{-10.2245}\\\Rightarrow t=6.993\ s$

Time taken by the thunderbird to stop is 6.993 seconds

Time the thunderbird was at the pit is 5 seconds

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{71.5^2-0^2}{2\times 350}\\\Rightarrow a=7.3\ m/s^2$

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{71.5-0}{7.3}\\\Rightarrow t=9.79\ s$

Time taken to accelerate back to 71.5 m/s is 9.79 seconds

Total time to this point is 6.993+5+9.79 = 21.783 seconds

The Mercedes Benz is moving at a constant velocity hence it has no acceleration and we use the formula

Distance = Speed × Time

⇒Distance = 71.5 × 21.783 = 1557.4845 m

The thunderbird has covered 250+350 = 600 m

So, the distance between them is 1557.4845-600 = 957.4845 m

7 0

3 years ago