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Maksim231197 [3]

3 years ago

14

Find the arc length of a semicircle with a Diameter of 10

1 answer:

vladimir1956 [14]3 years ago

5 0

Answer:

15.7079633

Step-by-step explanation:

hope it helps

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The cost of the ski team's trip is represented by the question: Where

Elina [12.6K]

The answer is: 30 skiers were participating in the ski trip.

Method:

$50S = $1,850 - $350 = $1,500

S = 1,500/50 = 30

Therefore, 30 skiers went on the trip

8 0

2 years ago

Write an expression for b divided by 6

Nonamiya [84]

B divided by 6

b / 6...." / " means divide

7 0

3 years ago

Read 2 more answers

A 15-ft ladder leans against a wall. The lower end of the ladder is being pulled away from the wall at the rate of 1.5 ft/sec. L

Aleks [24]

Answer:

The top of the ladder is sliding down at a rate of 2 feet per second.

Step-by-step explanation:

Refer the image for the diagram. Consider $\Delta ABC$ as right angle triangle. Values of length of one side and hypotenuse is given. Value of another side is not known. So applying Pythagoras theorem,

$\left ( AB \right )^{2}+\left ( BC \right )^{2}=\left ( AC \right )^{2}$

From the given data, $L=15\:ft=AC$ , $y=9\:ft=AB$ and $x=BC$

Substituting the values,

$\therefore \left ( 9 \right )^{2}+\left ( x \right )^{2}=\left ( 15 \right )^{2}$

$\therefore 81+x^{2}=225$

$\therefore x^{2}=225-81$

$\therefore x^{2}=144$

$\therefore \sqrt{x^{2}}=\sqrt{144}$

$\therefore x=\pm 12$

Since length can never be negative, so $x= 12$ .

Now to calculate $\dfrac{dy}{dt}$ again consider following equation,

$\left ( y \right )^{2}+\left ( x \right )^{2}=\left ( l \right )^{2}$

Differentiate both sides of the equation with respect to t,

$\dfrac{d}{dt}\left(y^2+x^2\right)=\dfrac{d}{dt}\left(l^2\right)$

Applying sum rule of derivative,

$\dfrac{d}{dt}\left(y^2\right)+\dfrac{d}{dt}\left(x^2\right)=\dfrac{d}{dt}\left(l^2\right)$

$\dfrac{d}{dt}\left(y^2\right)+\dfrac{d}{dt}\left(x^2\right)=\dfrac{d}{dt}\left(225\right)$

Applying power rule of derivative,

$2y\dfrac{dy}{dt}+2x\dfrac{dx}{dt}=0$

Simplifying,

$y\dfrac{dy}{dt}+x\dfrac{dx}{dt}=0$

Substituting the values,

$9\dfrac{dy}{dt}+12\times1.5=0$

$9\dfrac{dy}{dt}+18=0$

Subtracting both sides by 18,

$9\dfrac{dy}{dt}=-18$

Dividing both sides by 9,

$\dfrac{dy}{dt}= - 2$

Here, negative indicates that the ladder is sliding in downward direction.

$\therefore \dfrac{dy}{dt}= 2\:\dfrac{ft}{sec}$

7 0

3 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Mademuasel [1]

9514 1404 393

Answer:

see attached

Step-by-step explanation:

The attachment lists points on each graph.

a) The equation for a horizontal line is ...

y = constant

Here, the output value is always 5, so that is the constant in the equation:

y = 5

__

b) The graph is a straight line through the origin, so the equation is that of a proportion:

y = kx . . . . . for some constant of proportionality k

Using the point (x, y) = (-4, 2), we can find k from ...

k = y/x = 2/(-4) = -1/2

The equation of the line is ...

y = -1/2x

__

c) The graph has a rise of 3 units for each run of 1 unit, so the slope is ...

m = rise/run = 3/1 = 3

The y-intercept (where the line crosses the y-axis) is b = -2. Then the slope-intercept form of the equation is ...

y = mx + b . . . . . for slope m and y-intercept b

y = 3x - 2

_____

You can check that the equation is satisfied by each of the points listed. For example, ...

a) in = -4, out = y = 5 . . . matches table

b) in = 2, out = y = -1/2(2) = -1 . . . matches table

c) in = 1, out = y = 3(1) -2 = 1 . . . matches table

(You can check the other table values.)

4 0

3 years ago

Need help dont know how to do it need explanation aswell

nasty-shy [4]

CA: -a+a

AB: b+a

BC: -a+b or b-a

4 0

2 years ago