Daniel had $25 to spend at the fair. If the admission to the fair is $4 and the rides cost $1.50 each, what is the greatest numb
1 answer:
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Answer:
The probability that the student answers at least seventeen questions correctly is .
Step-by-step explanation:
Let the random variable <em>X</em> represent the number of correctly answered questions.
It is provided all the questions have five options with only one correct option.
Then the probability of selecting the correct option is,
There are <em>n</em> = 20 question in the exam.
It is also provided that a student taking the examination answers each of the questions with an independent random guess.
Then the random variable can be modeled by the Binomial distribution with parameters <em>n</em> = 20 and <em>p</em> = 0.20.
The probability mass function of <em>X</em> is:
Compute the probability that the student answers at least seventeen questions correctly as follows:
Thus, the probability that the student answers at least seventeen questions correctly is .
Answer:
Since our calculated value is outside than our critical value,, we have enough evidence to reject the null hypothesis at 5% of significance. So there is not nough evidence to conclude that mean for Ohio it's significantly different than the mean for Georgia.
Step-by-step explanation:
1) Data given and notation
represent the mean for Georgia
represent the mean for Ohio
represent the population standard deviation for Georgia
represent the population standard deviation for Ohio
sample size for Georgia
sample size for Ohio
z would represent the statistic (variable of interest)
represent the p value
2) Concepts and formulas to use
We need to conduct a hypothesis in order to check if the means are different for both groups, the system of hypothesis would be:
H0:
H1:
If we analyze the size for the samples both are higher than 30, we can assume that the normal distribution is the correct disirbution for the statistic, so for this case is better apply a z test to compare means, and the statistic is given by:
(1)
z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.
3) Calculate the statistic
We have all in order to replace in formula (1) like this:
4) Find the critical value
In order to find the critical value we need to take in count that we are conducting a two tailed test, so we are looking on the normal standard distribution a value that accumulates 0.025 of the area on the right and 0.975 of the area on the left. We can us excel or a table to find it, for example the code in Excel is:
"=NORM.INV(1-0.025,0,1)", and we got
5) Statistical decision
Since our calculated value is outside than our critical value,, and outside of (-1.96,1.96), we have enough evidence to reject the null hypothesis at 5% of significance. So there is not nough evidence to conclude that mean for Ohio it's significantly different than the mean for Georgia.
Answer:
See the attached figure.
Given:
u = (-3.5 , -1.5) and v = (-1.25 , 2.25)
So,
2v = 2 * (-1.25 , 2.25) = (-2.5, 4.5)
∴ 2v - u = (-2.5, 4.5) - (-3.5 , -1.5) = (1 , 6)
The graph of the vectors is as shown in the attached figure.
