I think that different liquids have different freezing points because every liquid consists of different atoms and different things that make up the atom causing them to have different freezing points.
Answer: The correct option is 4.
Explanation: All the options will undergo some type of radioactive decay processes. There are 3 decay processes:
1) Alpha decay: It is a decay process in which alpha particle is released which has has a mass number of 4 and a charge of +2.

2) Beta-minus decay: It is a decay in which a beta particle is released. The beta particle released has a mass number of 0 and a charge of (-1).

3) Beta-plus decay: It is a decay process in which a positron is released. The positron released has a mass number of 0 and has a charge of +1.

For the given options:
Option 1: This nuclei will undergo beta-plus decay process to form 

Option 2: This nuclei will undergo beta-minus decay process to form 

Option 3: This nuclei will undergo a beta minus decay process to form 

Option 4: This nuclei will undergo an alpha decay process to form 

Hence, the correct option is 4.
Answer:
1. smaller. 2. smaller. 3. greater
Explanation:
1. H−O−H angle is 104.45 and H−C−H angle is 109.5
2. O−S−O angle is 119 and F−B−F angle is 120
3. The F−S−F bond angle in SF₆ is 90 and F−Br−F bond angle in BrF₅ is 84.8
I think it's easiest to find the pOH from the given [OH-] first.
-log(1x10^-5)
pOH=5
Then find the pH.
pOH+pH=14
5+pH=14
pH=9
Then find the [H+] using the pH.
antilog(-9) (if you dont have an antilog button use 10^-9)
[H+]=1x10^-9