The annual rainfall (in inches) in a certain region is normally distributed with µ = 40 and σ = 4. What is the probability that
1 answer:
Answer:
P( That it will take over 10 years or more of a year with a rainfall above 50inches) = (0.9938)^10
Step-by-step explanation:
Since the annual rainfall is normally distributed,
Given: that
Mean (µ )= 40
and σ = 4.
Let X be normal random variables of the annual rainfall.
P(that there will be over 10 years or more before a year with a rainfall above 50 inches)
P(>50) = 1-P[X ≤50]
1 - P[X- μ/σ ≤ 50 - 40/4]
=1 - P [Z≤ 5/2]
=1 -Φ(5/2)
=1 - 0.9939
= 0.0062
P( the non occurrence of rainfall above 50 inches)
= 1-0.0062
=0.9938
ASSUMPTION:
P( That it will take over 10 years or more of a year with a rainfall above 50inches) =
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Answer:
Your answer would be:
57.75 or 57 3/4
(I will show how many of each length of twine that is on the graph)
Point 2 1/4:
2
Point 2 3/4:
4
Point 3:
1
Point 3 1/2:
2
Point 3 3/4:
3
Point 4:
1
Point 4 1/4:
4
We can show how much length in total Stevie used with the following equation:
(2 1/4 x 2) + (2 3/4 x 4) + ( 3 x 1 ) + ( 3 1/2 x 2 ) + (3 3/4 x 3 ) + (4 x 1 ) + (4 1/4 x 4)
Each smaller equation in paraphrases shows how much of each length of twine at each point with x's on the number line. Altogether it would equal 57.75 or 57 3/4.
Step-by-step explanation:
Have a great rest of your day
#TheWizzer
