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taurus [48]
3 years ago
5

is it true that parallel worlds exists? if yes or no, give proper reasons and proof. brainliest to the best ​

Physics
1 answer:
Daniel [21]3 years ago
5 0

Answer:

It is just a theory that multi verse exists. Researchers have found tracers of mirror particles which could only be from other universe.

Explanation:

Its said above.

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2.30 Suppose that the radius of a typical cell is 10 mm and that inside it 106 ATP molecules are hydrolyzed each second. What is
Ipatiy [6.2K]

Answer and Explanation: One ATP release approximately 30.5kJ/mol of energy. Using Avogadro's constant, it is known one mol corresponds to 6.02.10^{23} molecules, so 106 ATP molecules releases:

E = 30.5.10^{3}*\frac{106}{6.02.10^{23}}

E = 537.04.10^{-20}J

A cell is approximately a sphere. Volume of a sphere is given by

V = \frac{4}{3}.\pi.r^{3}

Changing radius from mm to m:

r = 10^{-2}m

Then, volume is

V = \frac{4}{3}.\pi.(10^{-2})^{3}

V = 4.2.10^{-6} m³

Power density is given by

power=\frac{energy}{volume}

power=\frac{537.04.10^{-20}}{4.2.10^{-6}}

power=128.10^{-14}

power = 12.8.10^{-15} W/m³

Power density for a the cell is 12.8.10^{-15} W/m³.

Power density for battery is

100 cm³ = 10^{-4}m³

power = \frac{15}{10^{-4}}

power = 15.10^{4}W/m³

Comparing cell and battery, battery has a greater power density.

5 0
4 years ago
The experimenter fom the video rotates on his stool, this time holding his empty hands in his lap. You stand on a desk above him
gtnhenbr [62]

Answer:

Explanation:

The experimenter is rotating on his stool with angular velocity ω ( suppose )

His moment of inertia is I say

We are applying no torque from outside . therefore , the angular momentum will remain the same

Thus angular momentum L = I ω = constant

Thus we can say I₁ ω₁ = I₂ω₂ = constant

here I₁ is the initial moment of inertia and ω₁ is the initial angular velocity

Similarly I₂ is the final moment of inertia and ω₂ is the final angular velocity

When a been bag is dropped on his lap , his moment of inertia increases due to increase in mass

In the above equation, when moment of inertia increases , the angular velocity decreases . So its motion of rotation will decrease .

7 0
3 years ago
Solution A has a specific heat of 2.0 J/g◦C. Solution B has a specific heat of 3.8 J/g◦C. If equal masses of both solutions start
fgiga [73]

Answer: 2. Solution A attains a higher temperature.

Explanation: Specific heat simply means, that amount of heat which is when supplied to a unit mass of a substance will raise its temperature by 1°C.

In the given situation we have equal masses of two solutions A & B, out of which A has lower specific heat which means that a unit mass of solution A requires lesser energy to raise its temperature by 1°C than the solution B.

Since, the masses of both the solutions are same and equal heat is supplied to both, the proportional condition will follow.

<em>We have a formula for such condition,</em>

Q=m.c.\Delta T.....................................(1)

where:

  • \Delta T= temperature difference
  • Q= heat energy
  • m= mass of the body
  • c= specific heat of the body

<u>Proving mathematically:</u>

<em>According to the given conditions</em>

  • we have equal masses of two solutions A & B, i.e. m_A=m_B
  • equal heat is supplied to both the solutions, i.e. Q_A=Q_B
  • specific heat of solution A, c_{A}=2.0 J.g^{-1} .\degree C^{-1}
  • specific heat of solution B, c_{B}=3.8 J.g^{-1} .\degree C^{-1}
  • \Delta T_A & \Delta T_B are the change in temperatures of the respective solutions.

Now, putting the above values

Q_A=Q_B

m_A.c_A. \Delta T_A=m_B.c_B . \Delta T_B\\\\2.0\times \Delta T_A=3.8 \times \Delta T_B\\\\ \Delta T_A=\frac{3.8}{2.0}\times \Delta T_B\\\\\\\frac{\Delta T_{A}}{\Delta T_{B}} = \frac{3.8}{2.0}>1

Which proves that solution A attains a higher temperature than solution B.

7 0
3 years ago
Where should you place the values of the independent variable when constructing a data table?
kobusy [5.1K]
<span>On the y-axis (the bottom of the table) hope this helps</span>
4 0
3 years ago
Read 2 more answers
2. Another car weighs 2000kg, you can push it .05 m/s?, how much force are you
Vesna [10]

Answer:

\boxed {\boxed {\sf 100 \ Newtons}}

Explanation:

We are asked to calculate the force you are applying to a car. According to Newton's Second Law of Motion, force is the product of mass and acceleration. Therefore, we can use the following formula to calculate force.

F= m \times a

The mass of the car is 2000 kilograms and the acceleration is 0.5 meters per second squared.

  • m= 2000 kg
  • a= 0.05 m/s²

Substitute the values into the formula.

F= 2000 \ kg \times 0.05 \ m/s^2

Multiply.

F= 100 \ kg *m/s^2

Convert the units. 1 kilogram meter per second squared is equal to 1 Newton. Our answer of 100 kilogram meters per second square is equal to 100 Newtons.

F= 100 \ N

You apply <u>100 Newtons</u> of force to the car.

7 0
3 years ago
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