Answer:
Making a vertical vector, we have a starting point at (-5,2) and an end point at (5,2) that will give us a vector of magnitude of 10 units.
Explanation:
In order to make vectors that have a magnitude of 10 units, the distance between the starting and ending points must be equal to 10.
The easiest way is to set points on either an horizontal or vertical line to make horizontal or vertical vectors.
We can have starting point at (-5,2) and then move up 10 units so we will be at the ending point (5,2), thus the distance between them is 10 units so the vector has a magnitude of 10 units.
We can verify that using the formula for the magnitude which requires first to find the vector.
So for the points we have
We can work with each component, for the x component we have 5-(-5) which give us 10 and for the y component we have 2-2 which give us 0, so the vector is
Thus its magnitude is
Thus we have verified our vector has a length 10.
Answer:The greater the mass, there greater then gravitational pull on their objects.
There greater the distance,the lower the gravitational pull between the object
Explanation:
Gravitational pull(force) is directly proportional to the products Of The masses. therefore if the mass increase,the gravitational pull(force) also increases.
Gravitational pull(force) is inversely proportional to distance.if the distance between the objects increases,the gravitational pull(force) decreases .
Answer:
maximum amplitude = 0.08 m
Explanation:
Given that
Time period T= 0.58 s
acceleration of gravity g= 9.8 m/s²
We know that time period of simple harmonic motion given as
T = 2π/ω
0.58 = 2π/ω
ω = 10.83rad/s
ω=angular frequency
Lets take amplitude = A
The maximum acceleration given as
a= ω² A
The maximum acceleration should be equal to g ,then block does not separate
a= ω² A
9.8 = 10.83² A
A = 0.08m
maximum amplitude = 0.08 m
Complete question:
Consider the hypothetical reaction 4A + 2B → C + 3D
Over an interval of 4.0 s the average rate of change of the concentration of B was measured to be -0.0760 M/s. What is the final concentration of A at the end of this same interval if its concentration was initially 1.600 M?
Answer:
the final concentration of A is 0.992 M.
Explanation:
Given;
time of reaction, t = 4.0 s
rate of change of the concentration of B = -0.0760 M/s
initial concentration of A = 1.600 M
⇒Determine the rate of change of the concentration of A.
From the given reaction: 4A + 2B → C + 3D
2 moles of B ---------------> 4 moles of A
-0.0760 M/s of B -----------> x
⇒Determine the change in concentration of A after 4s;
ΔA = -0.152 M/s x 4s
ΔA = -0.608 M
⇒ Determine the final concentration of A after 4s
A = A₀ + ΔA
A = 1.6 M + (-0.608 M)
A = 1.6 M - 0.608 M
A = 0.992 M
Therefore, the final concentration of A is 0.992 M.
These techniques are central to psychoanalytic therapy. They can be used alone or in combination with one another. Their purpose is to increase awareness and foster insight into the client's behavior and emotions
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