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asambeis [7]
3 years ago
11

A car is rounding a curve that is the arc of a circle with a radius of r . if the car has a constant speed of 10 m/s, and its ac

celeration is 5 m/s2 , what is the radius of the curve?
Physics
1 answer:
aev [14]3 years ago
4 0
The formula to find the radius is R=V^2/A or Radius=Velocity^2/Acceleration so that means
R=V^2/A
10^2/5=R
100/5=R
R=20m
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Rocks A and B are located at the same height on top of a hill. The mass of rock A is twice the mass of rock B. How does the pote
Ronch [10]

Potential energy is defined by formula

U = mgh

here

m = mass

g = acceleration due to gravity

h = height

Now here two different stones are located at same height

while mass of stone A is twice that of stone B

so here we can say potential energy of A is

U_a = (2m)gh

Similarly potential energy of B is

U_b = mgh

now if we take the ratio of two energy

\frac{U_a}{U_b} = 2

so we can say potential energy of stone A is two times the potential energy of B

7 0
3 years ago
In 1923, the United States Army (there was no U.S. Air Force at that time) set a record for in-flight refueling of airplanes. Us
dybincka [34]

Answer:

1.95m/s

Explanation:

Please view the attached file for the detailed solution.

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6 0
3 years ago
A 60-kg cheetah reaches a speed of 30 m/s as it chases its prey.What is the kinetic energy of the cheetah?
Rama09 [41]
The answer would be 27,000 Joules because (1/2) m v^2 =30*900 which equals 27,000 J
4 0
3 years ago
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Two long, parallel wires separated by 2.00 cm carry currents in opposite directions. The current in one wire is 1.75 A, and the
Natasha_Volkova [10]

The force per unit length between the two wires is 6.0\cdot 10^{-5} N/m

Explanation:

The magnitude of the force per unit length exerted between two current-carrying wires is given by

\frac{F}{L}=\frac{\mu_0 I_1 I_2}{2\pi r}

where

\mu_0 = 4\pi \cdot 10^{-7} Tm/A is the vacuum permeability

I_1, I_2 are the currents in the two wires

r is the separation between the two wires

For the wires in this problem, we have

I_1 = 1.75 A

I_2 = 3.45 A

r = 2.00 cm = 0.02 m

Substituting into the equation, we find

\frac{F}{L}=\frac{(4\pi \cdot 10^{-7})(1.75)(3.45)}{2\pi (0.02)}=6.0\cdot 10^{-5} N/m

Learn more about current and magnetic fields:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

brainly.com/question/3874443

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4 0
3 years ago
What should be done to lift the same load by applying less effort on an inclined plane​
Scorpion4ik [409]

Answer:

Reduce the friction at the surface

Explanation:

If you can reduce the friction between the load and the plane less effort will be required as you are not having to apply effort to overcome friction.

5 0
2 years ago
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