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lions [1.4K]
3 years ago
6

2x+7=27 and 3x+1=28 does 2x+7= 3x+1

Mathematics
2 answers:
Sladkaya [172]3 years ago
6 0
Assuming that you are asking this :

Does 2x + 7 = 27 equal 3x + 1 = 28 ? 

Let's first solve for 2x + 7 = 27

2x + 7 = 27

Subtract 7 from both sides.

2x = 27 - 7

Simplify.

2x = 20

Divide both sides by 2.

x = 10

Then, solve for 3x + 1 = 28

3x + 1 = 28

Subtract both sides by 1.

3x = 28 - 1

Simplify.

3x = 27

Divide both sides by 3.

x = 9

10 ≠ 9 therefore, 2x + 7 ≠ 3x + 1

~Hope I helped!~ :)


Savatey [412]3 years ago
5 0
Hey there!

2x + 7 = 27
2x = 20
x = 10

3x + 1 = 28
3x = 27
x = 9

The values for both of these equations are 9 and 10; therefore, the answers are not equivalent.

I hope this helps!
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Which of the following is a trinomial?
Sedaia [141]

Answer:

A) c^2 + c + 6

Step-by-step explanation:

We have been given four choices out of which we need to select the choice which is trinomial.

Trinomial means polynomial having three terms.

A) c2 + c + 6

It has 3 terms.

B) c2 − 16

It has 2 terms.

C) −8c

It has 1 term.

D) c3 + 4c2 − 12c + 7

It has 4 terms.

We see that only choice A) has three terms.

Hence correct choice is A) c^2 + c + 6


5 0
3 years ago
Hal has a steel barrel with a diameter of 6 feet that can be filled to a depth of 4.6 feet with oil. What is the volume of the b
scoray [572]

Answer:

129.996 cubic feet

Step-by-step explanation:

Assuming that the barrel is a perfect cylinder, we can use the formula to find the volume:

\pi(r)^2(h)

First, we have to find the radius, which is:

D = 2r

So the radius is 3 feet, since it is half of the diameter. Then, we plug in the values.

3.14(3)^2(4.6)

Now, we solve. Exponents are first...

3.14(9)(4.6)

Now multiply left to right.

28.26(4.6)

129.996 cubic feet

Therefore, the barrel can hold 129.996 cubic feet of oil. Hope this helps you!

3 0
3 years ago
When a number is divided by 5 the answer is 3 remainder 4, what is that number?
skelet666 [1.2K]

We know that 5 fits entirely into our number three times, and then there's a remainder of 4.

If 5 fits three times exactly, it means that our number is at least 15 (5x3).

From here, we have a remainder of 4, which leads to 15+4=19

5 0
2 years ago
United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the n
Ivanshal [37]

Answer:

<u><em>a) The probability that exactly 4 flights are on time is equal to 0.0313</em></u>

<u><em></em></u>

<u><em>b) The probability that at most 3 flights are on time is equal to 0.0293</em></u>

<u><em></em></u>

<u><em>c) The probability that at least 8 flights are on time is equal to 0.00586</em></u>

Step-by-step explanation:

The question posted is incomplete. This is the complete question:

<em>United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the number on-time flights is recorded. Round answers to 3 significant figures. </em>

<em>a) The probability that exactly 4 flights are on time is = </em>

<em>b) The probability that at most 3 flights are on time is = </em>

<em>c)The probability that at least 8 flights are on time is =</em>

<h2>Solution to the problem</h2>

<u><em>a) Probability that exactly 4 flights are on time</em></u>

Since there are two possible outcomes, being on time or not being on time, whose probabilities do not change, this is a binomial experiment.

The probability of success (being on time) is p = 0.5.

The probability of fail (note being on time) is q = 1 -p = 1 - 0.5 = 0.5.

You need to find the probability of exactly 4 success on 9 trials: X = 4, n = 9.

The general equation to find the probability of x success in n trials is:

           P(X=x)=_nC_x\cdot p^x\cdot (1-p)^{(n-x)}

Where _nC_x is the number of different combinations of x success in n trials.

            _nC_x=\frac{x!}{n!(n-x)!}

Hence,

            P(X=4)=_9C_4\cdot (0.5)^4\cdot (0.5)^{5}

                                _9C_4=\frac{4!}{9!(9-4)!}=126

            P(X=4)=126\cdot (0.5)^4\cdot (0.5)^{5}=0.03125

<em><u>b) Probability that at most 3 flights are on time</u></em>

The probability that at most 3 flights are on time is equal to the probabiity that exactly 0 or exactly 1 or exactly 2 or exactly 3 are on time:

         P(X\leq 3)=P(X=0)+P(X=1)+P(X=2)+P(X=3)

P(X=0)=(0.5)^9=0.00195313 . . . (the probability that all are not on time)

P(X=1)=_9C_1(0.5)^1(0.5)^8=9(0.5)^1(0.5)^8=0.00390625

P(X=2)=_9C_2(0.5)^2(0.5)^7=36(0.5)^2(0.5)^7=0.0078125

P(X=3)= _9C_3(0.5)^3(0.5)^6=84(0.5)^3(0.5)^6=0.015625

P(X\leq 3)=0.00195313+0.00390625+0.0078125+0.015625=0.02929688\\\\  P(X\leq 3) \approx 0.0293

<em><u>c) Probability that at least 8 flights are on time </u></em>

That at least 8 flights are on time is the same that at most 1 is not on time.

That is, 1 or 0 flights are not on time.

Then, it is easier to change the successful event to not being on time, so I will change the name of the variable to Y.

          P(Y=0)=_0C_9(0.5)^0(0.5)^9=0.00195313\\ \\ P(Y=1)=_1C_9(0.5)^1(0.5)^8=0.0039065\\ \\ P(Y=0)+P(Y=1)=0.00585938\approx 0.00586

6 0
3 years ago
Solve ax-b/d=c, for x
Kitty [74]

Answer:

x = cd + b / a

Step-by-step explanation:

ax - b / d = c

ax - b = cd

ax = cd + b

x = cd + b / a

5 0
3 years ago
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