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frosja888 [35]
3 years ago
5

The town of seaside needs to build a new power plant the old coal burning plant produces too much pollution and if no longer saf

e the mayor decides that he will do some research on alternative forms of energy like nuclear plants and solar power plants .what types of resources are reliable?
Physics
1 answer:
drek231 [11]3 years ago
7 0

To generate clean energy the mayor my build the fooling type of energy plants:

wind farms

solar power plants

wave power plants

Explanation:

At the seaside there are winds all over the year and that can be transformed in electrical energy by a wind turbine. The mayor can build a on-shore wind farm (reduced consts) and may also build off-shore wind farms (but these have an increased cost).

The second option is to build solar power plants. It will be cost effective if the people in the town will install solar panels on the building roofs. In this way you decrease the costs with the transportation of electrical energy.

The third option is to install wave power plants which harvest energy from the sea waves. It is a rather new technology, in comparison with the other two, but the initial consts can be amortized over time.

All three options will provide clean energy.

Right now nuclear plants have a very expensive initial costs and they may not be afforded by small towns.

Learn more about:

clean energy sources

brainly.com/question/235226

#learnwithBrainly

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Determine the power that needs to besupplied by the fanifthe desired velocity is 0.05 m3/s and the cross-sectional area is 20 cm
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Answer:

A fan with an energy efficiency of 30 % would need 62.5 watts to bring a desired volume flow of 0.05 cubic meters per second through a cross-sectional area of 20 square centimeters.

Explanation:

Complete statement is: <em>Determine the power that needs to besupplied by the fan if the desired velocity is 0.05 cubic meters per second and the cross-sectional area is 20 square centimeters.</em>

From Thermodynamics and Fluid Mechanics we know that fans are devices that work at steady state which accelerate gases (i.e. air) with no changes in pressure. In this case, mechanical rotation energy is transformed into kinetic energy. If we include losses due to mechanical friction, the Principle of Energy Conservation presents the following equation:

\eta\cdot \dot W = \dot K

\dot W = \frac{\dot K}{\eta} (Eq. 1)

Where:

\eta - Efficiency of fan, dimensionless.

\dot W - Electric power supplied fan, measured in watts.

\dot K - Rate of change of kinetic energy of air in time, measured in watts.

From definition of kinetic energy, the equation above is now expanded:

\dot W = \frac{\rho_{a}\cdot \dot V}{2\cdot \eta}\cdot \left(\frac{\dot V}{A_{s}} \right)^{2} (Eq. 2)

Where:

\rho_{a} - Density of air, measured in kilograms per cubic meter.

\dot V - Volume flow, measured in cubic meters per second.

A_{s} - Cross-sectional area of fan, measured in square meters.

If we know that \rho_{a} = 1.20\,\frac{kg}{m^{3}}, \dot V = 0.05\,\frac{m^{3}}{s}, \eta = 0.3 and A_{s} = 20\times 10^{-4}\,m^{2}, the power needed to be supplied by the fan is:

\dot K = \left[\frac{\left(1.20\,\frac{kg}{m^{3}} \right)\cdot \left(0.05\,\frac{m^{3}}{s} \right)}{2\cdot (0.3)} \right]\cdot \left(\frac{0.05\,\frac{m^{3}}{s} }{20\times 10^{-4}\,m^{2}} \right)^{2}

\dot K = 62.5\,W

A fan with an energy efficiency of 30 % would need 62.5 watts to bring a desired volume flow of 0.05 cubic meters per second through a cross-sectional area of 20 square centimeters.

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