If a rod attached to the approaching charge if the rod consists of "stiff" spring-like bonds for which atoms undergo small oscil
1 answer:
Answer: hello options related to your question is missing attached below is the missing part of your question
answer: No charge of the length of the bonds expected because the rod did not touch the charge source ( option A )
Explanation:
When the Charge is first, Furthest away and second and closest to the source charge. <em>The spring like bonds can be said to have No charge of the length of the bonds expected because the rod did not touch the charge source </em><em>when Furthest away the bond with charge will be less effective </em>
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Answer:
p_{f} = 6 m / s
Explanation:
We can solve this exercise using conservation of momentum. For this we define a system formed by the two balls, so that the forces during the collision have been intense and the moment is preserved
Initial instant. Before the crash
p₀ = m v +0
Final moment. Right after the crash
= (m + m) v_{f}
how the moment is preserved
p₀ = p_{f}
m v = 2 m v_{f}
v_{f} = v / 2
we calculate
v_{f} = 12/2
p_{f} = 6 m / s
Answer:
a)
b)
c)
Explanation:
We have:
m: is the ball's mass = 1.5 kg
v₀: is the initial speed = 15 m/s
g: is the gravity acceleration = 9.81 m/s²
a) In the initial position we have:
h: is the height = 0
The potential energy is given by:
The kinetic energy is:
And the mechanical energies:
b) At 5 m above the initial position we have:
h = 5 m
The potential energy is:
Now, to find the kinetic energy we need to calculate the speed at 5 m:
And the mechanical energies:
c) At its maximum height:
: is the final speed = 0
Now, the potential, kinetic and mechanical energies are:
I hope it helps you!
Answer:
Explanation:
Given
acceleration is given by
where
Also acceleration is given by
at
when air drag is neglected maximum height reached is
Answer:
The kinetic energy of the particle will be 12U₀
Explanation:
Given that,
A particle is launched from point B with an initial velocity and reaches point A having gained U₀ joules of kinetic energy.
Constant force = 12F
According to question,
The kinetic energy is
....(I)
Constant force = 12F
A resistive force field is now set up ,
Resistive force is given by,
When the particle moves from point B to point A then,
We need to calculate the kinetic energy
Using formula for kinetic energy
Put the value of
Now, from equation (I)
Hence, The kinetic energy of the particle will be 12U₀.
