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maksim [4K]
3 years ago
8

Both atypical and traditional antipsychotics _____ levels of _____.

Physics
1 answer:
LiRa [457]3 years ago
5 0

Answer:

Both atypical and traditional antipsychotics <u>blocks</u> levels of<u> </u><u>serotonin</u><u>.</u>

Explanation:

These drugs are capable of reducing or turning off positive psychotic symptoms such as hallucinations, delusions, and language and behavior disorder.

In addition to also acting as mood stabilizers, they have an impact on mania, depression, and produce low anxiety.

These anti-psychotics work on the 5-HT2A receptor, it belongs to the family of serotonin receptors and it is a G protein-coupled receptor. 5-HT is short for 5-hydroxy-tryptamine, the chemical name for serotonin.

This receptor became notorious for its importance as a target for drugs like LSD. Later it became important again due to the action of many antipsychotic drugs, especially atypical ones.

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A coil of wire with 50 turns lies in the plane of the page and has an initial area of 0.140 m2. The coil is now stretched to hav
DENIUS [597]

Answer:

Magnitude of induced emf will be 87.5 volt

Direction of induced emf will be clockwise  

Explanation:

We have given number of turns in the coil N = 50

Initial area A=0.140m^2

Time is given dt = 0.1 sec

Magnetic field B = 1.25 T

From Faraday's law of electromagnetic induction

ne=-N\frac{d\Phi }{dt}=-NA\frac{dB}{dt}

e=-50\times 0.140\times \frac{1.25}{0.1}=-87.5volt

So magnitude of induced emf is 87.5 volt

Direction of induced emf will be clockwise

7 0
4 years ago
A bucket filled with water has a mass of 54 kg and is hanging from a rope that is wound around a 0.050 m radius stationary cylin
Lubov Fominskaja [6]

Answer:

The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.

Explanation:

Given that,

Mass of bucket = 54 kg

Radius = 0.050 m

We need to calculate the magnitude of the torque the bucket produces around the center of the cylinder

Using formula of torque

\tau=F\times r

\tau=mg\times r

Where, m = mass

g = acceleration due to gravity

r = radius

Put the value into the formula

\tau=54\times9.8\times0.050

\tau=26.46\ N-m

Hence, The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.

3 0
3 years ago
A dockworker applies a constant horizontal force of 73.0 N to a block of ice on a smooth horizontal floor. The frictional force
vivado [14]

Answer:

a) 57.0 kg b) 24.2 m

Explanation:

a) According Newton's second law, the applied force is equal to the product of the mass times the acceleration.

As the force is constant, the acceleration is constant too.

In this case, as we have as givens the distance and the time, and also we know that the block is starting form rest, we can get the acceleration as follows:

d = 1/2 * a * t² ⇒ a = 2d / t² ⇒ a= 2* 13.0 m / (4.5)² s² = 1.28 m/s²

Replacing in the Newton's 2nd Law equation:

F = m*a ⇒ m = F/a = 73.0 N / 1.28 m/s = 57.0 Kg

b) At t=4.5 s, applying the definition of acceleration, we can get the value of the velocity at that time, as follows:

v= a* t = 1.28 m/s * 4.5 s = 5.76 m/s

If the worker stops pushing at the end of the 4. 5 s, this means (neglecting friction) that from that time omwards, no net force acts on the block, so it continues moving at constant speed.

In order to get the distance moved in the next 4.20 sec, as it is moving at constant speed, we neeed just to apply the definition of velocity:

v= Δx / Δt  ⇒ Δx = v* Δt = 5.76 m/s * 4.2 m = 24.2 m

So, the total distance traveled during all the time (9.1 s) is just the sum of the 13.0 m advanced during the time when there was a constant force applied, and the last 24.2 m at constant speed, as follows:

d = 13.0 + 24.2 = 37.2 m

3 0
3 years ago
a boy throws a small stone into a pond. waves spread out from where the stone hits the water and travel to the side of the pond.
stich3 [128]

Answer: 1.6Hz                                                                                          

foe[vqefmvkeqmvkevkefmvqelkfveklveqv

4 0
3 years ago
A freight train rolls along a track with considerable momentum. If it rolls at the same speed but has twice as much mass, its mo
GREYUIT [131]

Answer:

doubled

Explanation:

<u>Step 1</u>. Linear momentum (p) = mass X velocity = mv

p = mv -----equation 1

<u>Step 2</u>. if the mass is now twice and speed is same

p = (2*m)v -----equation 2

solving equation 1 and 2 together,

p = mv = 2mv

p = 2

Therefore, its momentum is doubled

7 0
3 years ago
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