Answer:
i am guessing for reflection but not so sure
Answer:
Explanation:
a ) The motion is one dimensional , so motion is along x - axis , starting from origin ( 0 , 0 )
b ) Initial velocity is 18.5 m /s when boat is situated at origin . When he displaces by 250 m along x axis and his position is ( 250 , 0 ) along x axis , his velocity becomes 36 m /s . Both his velocity and acceleration is along x - axis.
c ) Initial velocity vi = 18.5 m /s
final velocity vf = 36 m/s
Displacement x = 250 m
Acceleration a = ?
Most appropriate formula is given below .
vf² = vi² + 2 a x
2ax = vf² - vi²
x = ( vf² - vi² ) / 2 a
d )
Putting the given values
36² - 18.5² / 2 x 250
= 1296 - 342.25 / 500
= 1.9 m /s².
f ) Time interval t = ?
Required formula
vf = vi + at
t = (vf - vi ) / a
Putting the values
t = (30 - 18.5) / 1.9
= 6.05 second .
Explanation:
According to the law of conservation of energy
,
Potential energy = kinetic energy
I = 
![mgh = [\frac{1}{2} \times mv^{2}] + [\frac{1}{2} \times (\frac{mr^{2}}{2}) \frac{v^{2}}{r^{2}}]](https://tex.z-dn.net/?f=mgh%20%3D%20%5B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20mv%5E%7B2%7D%5D%20%2B%20%5B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20%28%5Cfrac%7Bmr%5E%7B2%7D%7D%7B2%7D%29%20%5Cfrac%7Bv%5E%7B2%7D%7D%7Br%5E%7B2%7D%7D%5D)
mgh = ![[\frac{1}{2} \times mv^{2}] + [\frac{1}{4} \times mv^{2}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20mv%5E%7B2%7D%5D%20%2B%20%5B%5Cfrac%7B1%7D%7B4%7D%20%5Ctimes%20mv%5E%7B2%7D%5D)
v = 7.4 m/s
thus, we can conclude that the translational speed of the cylinder when it leaves the incline is 7.4 m/s.
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