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andrezito [222]
3 years ago
15

What is -4 + (3)(-8) +7 using the code PEMDAS?

Mathematics
2 answers:
son4ous [18]3 years ago
5 0
-8 times 3 first = -24
-4+-24= -28
-28 + 7 = -21
Answer -21
Harman [31]3 years ago
3 0

Answer:

-21

Step-by-step explanation:

-4 + (3)(-8) + 7

-4 + -24 + 7 <-- I used the (M) for multiplication

-28 + 7 <-- I used the (A) for addition

-21 <-- I used the (A) for addition again!

Your answer is -21.

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Solve the equations in two different ways:6p=0.6(5p+15)
Damm [24]

Answer:

Step-by-step explanation:

1st way:

Solve directly

6p=0.6(5p+15)

Open bracket

6p = 3p + 9

Collecting like terms

6p - 3p = 9

3p = 9

Dividing by 3

p = 9/3

p = 3

2nd way:

6p=0.6(5p+15)

Convert the decimal to fraction

6p= 6/10(5p+15)

6p= 3/5(5p+15)

6p= 3/5(5p) +3/5(15)

6p = 3p + 9

Collecting like terms

6p - 3p = 9

3p = 9

Dividing by 3

p = 9/3

p = 3

6 0
4 years ago
What is the equation of the line parallel to 4x+2y=8 and passing through the point (0,1)? Write the equation in slope-intercept
Ksenya-84 [330]
4x+2y=8
-4 -4
2y 4
6y
3 0
3 years ago
Read 2 more answers
You are giving a rectangle with dimensions of: length = 60 inches and width = 4j. The perimeter of the rectangle is 400 inches.
Illusion [34]

Answer:

perimeter is sum of all four sides; two of which are '4j' and other two are 60 inches each

Step-by-step explanation:

P= 2(4j) + 2(60)

We know perimeter is 400 inches

400 = 8j + 120

8j = 280

j = 35

4 0
3 years ago
Match each division expression to its quotient 3/5 divided by 5
Bogdan [553]
3/5/5
3/5/5/1
(3/5)(1/5) - flip when dividing
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6 0
3 years ago
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Find the area of a 2-inch-wide decorative border around a rectangular canvas painting, where L is the length and W is the width
lions [1.4K]

Answer:

  4L +4W +16 square inches

Step-by-step explanation:

The area of the border is the equivalent of that of a rectangle with a width equal to the width of the border, and a length equal to the length of the midline of the border. That length is the perimeter of the rectangle that is L+2 units long and W+2 units wide.

  border midline length = 2((L+2) +(W+2)) = 2L +2W +8

Then the border area is ...

  border area = (border width)(border length) = (2)(2L +2W +8)

  border area = 4L +4W +16 . . . square inches

_____

You can also figure this as the difference between the area of the rectangle with the border and the area of the rectangle inside the border:

  border area = total area - canvas area

  = (L+4)(W+4) -LW = LW +4L +4W +16 -LW

  = 4L +4W +16 . . . . square inches

4 0
3 years ago
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