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katen-ka-za [31]
3 years ago
5

Tacoma's population in 2000 was about 200 thousand, and has been growing by about 8% each year. If this continues, what will Tac

oma's population be in 2014?
Mathematics
1 answer:
Anestetic [448]3 years ago
5 0

Answer:

Tacoma's population in 2014 will be 587,439 people

Step-by-step explanation:

we know that

The equation of a exponential growth function  is given by the formula

y=a(1+r)^x

where

y is Tacoma's population in thousand

x is the number of years since 2000

r is the rate of change

a is the initial value

we have

a=200\\r=8\%=8/100=0.08

substitute

y=200(1+0.08)^x

y=200(1.08)^x

what will Tacoma's population be in 2014?

Find the value of x

x=2014-2000=14\ years

substitute the value of x

y=200(1.08)^{14}=587.439\ thousand

therefore

Tacoma's population in 2014 will be 587,439 people

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Order of Operation
Sphinxa [80]

<em><u>45(x)-20 </u></em>

x=hours

7 hours

x=7

<em><u>45(7)-20 =295</u></em>

4 0
2 years ago
Read 2 more answers
Let f(x)=241+3e−1.3x . What is the point of maximum growth rate for the logistic function f(x) ? Round your answer to the neares
FromTheMoon [43]

Answer:

The point of maximum growth is at x=0.82

Step-by-step explanation:

Given a logistic function

f(x)=\frac{24}{1+e^{-1.3x}}

we have to find the point of maximum growth rate for the logistic function f(x).

From the graph we can see that the carrying capacity or the maximum value of logistic function f(x) is 24 and the point of maximum growth is at y=\frac{24}{2} i.e between 0 to 12

So, we can take y=\frac{24}{2} and then solve for x.

\frac{24}{2}=\frac{24}{1+e^{-1.3x}}

⇒ 2=1+3\exp{-1.3x}

⇒ 1=3.\exp{-1.3x} ⇒ \frac{1}{3}=\exp{-1.3x}

                             ⇒ log 3=-1.3x

                             ⇒ -0.4771=-1.3.x ⇒ x=0.82

Hence, the point of maximum growth is at x=0.82


5 0
3 years ago
................................find 8% of 2.36.
slega [8]
2,36 ------- 100%
x ---------    8%
----------------------

 x = 2,36*8/100 = 0,18 

hope helped 
8 0
2 years ago
A jet airplane, departing on time and flying between two airports at an average speed of $540 mph, arrives eight minutes late. D
Leokris [45]
<h3>Answer:   3240 miles</h3>

========================================

Work Shown:

Convert the given speeds from "miles per hour" to "miles per minute"

540 mi/hr = (540 mi/hr)*(1 hr/60 min)

540 mi/hr = (540/60) (mi/min)

540 mi/hr = 9 mi/min

480 mi/hr = (480 mi/hr)*(1 hr/60 min)

480 mi/hr = (480/60) (mi/min)

480 mi/hr = 8 mi/min

---------------

Let,

  • d = distance between two airports
  • x = time in minutes it takes the plane to travel 9 mi/min
  • y = time in minutes it takes the plane to travel 8 mi/min

If the plane travels 9 mi/min, then,

distance = rate*time

d = 9*x

d/9 = x

x = d/9

Similarly if the plane travels 8 mi/min, then,

d = 8*y

d/8 = y

y = d/8

Subtract the time values y and x

y-x = d/8 - d/9

y-x = 9d/72 - 8d/72

y-x = (9d-8d)/72

y-x = d/72

This difference represents 45 minutes because 53 - 8 = 45. The 53 and 8 are from the fact the plane is late 53 minutes and 8 minutes.

In other words, y-x = 45, so d/72 = 45 which solves to d = 3240 when you multiply both sides by 72.

---------------------------------

Extra Info:

If d = 3240, then

x = d/9 = 3240/9 = 360

y = d/8 = 3240/8 = 405

So y-x = 405 - 360 = 45

If the plane travels 9 mi/min (aka 540 mph) then it spends 360 minutes (6 hours) doing so. If the plane travels 8 mi/min (480 mph) then it spends 405 minutes (6 hrs, 45 min) doing so. So this is a more detailed look at why the time gap is 45 minutes.

4 0
3 years ago
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sammy [17]
1/4, because in 1/3, you would only need 3 parts to get one whole, but in 1/4, you would need 4 parts to get a whole. 
3 0
3 years ago
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