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katen-ka-za [31]
3 years ago
5

Tacoma's population in 2000 was about 200 thousand, and has been growing by about 8% each year. If this continues, what will Tac

oma's population be in 2014?
Mathematics
1 answer:
Anestetic [448]3 years ago
5 0

Answer:

Tacoma's population in 2014 will be 587,439 people

Step-by-step explanation:

we know that

The equation of a exponential growth function  is given by the formula

y=a(1+r)^x

where

y is Tacoma's population in thousand

x is the number of years since 2000

r is the rate of change

a is the initial value

we have

a=200\\r=8\%=8/100=0.08

substitute

y=200(1+0.08)^x

y=200(1.08)^x

what will Tacoma's population be in 2014?

Find the value of x

x=2014-2000=14\ years

substitute the value of x

y=200(1.08)^{14}=587.439\ thousand

therefore

Tacoma's population in 2014 will be 587,439 people

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Answer:

  14,201 years

Step-by-step explanation:

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We went the amounts to be equal:

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Dividing by 1000(1 +0.07/365)^(365t), we have ...

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Taking logs, we have ...

  t×ln(1.00000671149321522) = ln(1.1)

  t = ln(1.1)/ln(1.00000671149321522) ≈ 0.09531018/(6.7114704·10^-6)

  t ≈ 14,201.09 . . . . . years

It will take about 14,201 years for the investments to be equal.

_____

<em>Additional comment</em>

The investment value at that time will be about $5.269·10^434. (That's a larger number than <em>anything</em> countable in the known universe, including energy quanta.)

These calculations are beyond the ability of many calculators, so might need to be carefully rewritten if the calculator only keeps 10 significant digits, or only manages exponents less than 100.

This shows that daily compounding is very close in effect to continuous compounding. It would take almost 150 years to make a difference of 0.1% in value.

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