Jason ran around his house 3 times which was a total of 274.5 feet. If the length of his house is 30.5 feet, what is the width o
f the house?
1 answer:
Answer:
Width of the house is 15.25 feet.
Step-by-step explanation:
Jason ran around his house = 3 times
In this run he covered total distance = 274.5 feet
Perimeter of the house = 2(length + width)
= 2(30.5 + width)
Perimeter of the house is the distance covered by Jason in one round.
So, distance covered in 3 rounds = 3[2(30.5 + width)]
274.5 = 6(30.5 + width)
274.5 = 6(30.5 + width)
45.75 = 30.5 + width
width = 45.75 - 30.5
width = 15.25 feet
Therefore, width of the house is 15.25 feet.
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Answer: 352
Step-by-step explanation:
To find the Lateral area of a square pyramid , we will follow the three steps below:
1. Find the perimeter of the base
2. Multiply the perimeter by the slant height
3. Divide the result above by 2
That is :
The lateral surface area of a regular pyramid is lateral area = perimeter of base x slant height of pyramid) ÷ 2.
Applying the formula above:
1. The base is a square , therefore the perimeter of a square is 4L , That is
Perimeter = 4(8)
Perimeter = 32m
2. Perimeter x slant height , that is
32 x 22 = 704m
3. Dividing the result by 2 , we have :
704/2 = 352
Therefore , the Lateral area of the pyramid is 352