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Degger [83]
3 years ago
8

Three identical bottles of soda are used in an experiment. One of the bottles is left at room temperature, another is cooled, an

d another is
heated. Next, the bottles are opened and balloons are placed on top to capture the escaping gas. The temperatures and results are shown.
2°C
22°C
40°C
Which statement is true about the warmest bottle?
A The unopened bottle originally contained the most amount of gas.
B. The unopened bottle originally contained the least amount of gas.
C. The smallest volume of gas has escaped from it into the balloon.
D. The greatest volume of gas has escaped from it into the balloon.
Chemistry
1 answer:
Alina [70]3 years ago
5 0

Answer:

It should be A.The unopened bottle originally contained the most amount of gas

Explanation:

not sure it really is a so dont come at me if its wrong

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A Downs cell operating at 77.0 A produces 31.0 kg of Na.(a) What volume of Cl₂(g) is produced at 1.0 atm and 540.°C?
nignag [31]

Volume of Cl₂(g) is produced at 1.0 atm and 540.°C=4.5×10^4 L

As per the evenly distributed response

2NaCl (g) ----> 2Na(l)+ Cl2(g)

Calculate the amount of Cl2 that was formed as indicated below:

Moles of Cl2 = 31.0 kg of Na x (1000* 1 * 1 / 1*23* 2)

                   = 673.9 mol

P is equal to 1.0 atm, and T is equal to 813.15 K

when converted to Kelvin by multiplying by a factor of 273.15.

Using Cl2 as an ideal gas, determine the in the following volume:

volume = nRT/P

= 673.9 * 0.0821 * 813.15/ 1

=4.5×10^4 L

As a result, the volume of Cl2 under the given circumstances =4.5×10^4 L

Learn more about Volume here:

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3 0
2 years ago
a 68.4-g sample of potassium chloride was added to 200.0g of water at 20 degrees C. Is the solution saturated, unsaturated, or s
Thepotemich [5.8K]

Answer is: the solution is saturated.

Solubility of potassium chloride (KCl) on 20°C is  34.2 grams in 100 grams of water, so in 200 grams of water will dissolve two times more salt (68.4 g).

Saturated solution contains the maximum concentration of a solute dissolved in the solvent (usually water) and if extra solute is add to saturated solution, that solute will not dissolve.

The amount of solute that can be dissolved in a solvent depends of chemical composition, temperature and pressure.

7 0
4 years ago
Read 2 more answers
What is the molarity of a solution made by adding 0.720 mole of NaOH to 2.40 liters of water
WITCHER [35]

Answer:

Molarity = 0.3 M

Explanation:

Given data:

Moles of NaOH = 0.720 mol

Volume of water = 2.40 L

Molarity = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Molarity = 0.720 mol / 2.40 L

Molarity = 0.3 mol/L

Molarity = 0.3 M

7 0
3 years ago
a molecule of ozone gas has has three atoms of oxygen . witch of these describes ozone most specifically?
AURORKA [14]

The best answer choice you could go for is B pure substance, a pure substance is a compound that is made of one element, like a diamond.

8 0
4 years ago
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The Haber Process synthesizes ammonia at elevated temperatures and pressures. Suppose you combine 1580 L of nitrogen gas and 351
ikadub [295]

Answer : The volume of reactant measured at STP left over is 409.9 L

Explanation :

First we have to calculate the moles of N_2 and H_2 by using ideal gas equation.

<u>For N_2 :</u>

PV_{N_2}=n_{N_2}RT

where,

P = Pressure of gas at STP = 1 atm

V = Volume of N_2 gas = 1580 L

n = number of moles N_2 = ?

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

1atm\times 1580L=n_{N_2}\times (0.0821L.atm/mol.K)\times 273K

n_{N_2}=70.49mole

<u>For H_2 :</u>

PV_{H_2}=n_{H_2}RT

where,

P = Pressure of gas at STP = 1 atm

V = Volume of H_2 gas = 3510 L

n = number of moles H_2 = ?

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

1atm\times 3510L=n_{H_2}\times (0.0821L.atm/mol.K)\times 273K

n_{H_2}=156.6mole

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

From the balanced reaction we conclude that

As, 3 mole of H_2 react with 1 mole of N_2

So, 156.6 moles of H_2 react with \frac{156.6}{3}\times 1=52.2 moles of N_2

From this we conclude that, N_2 is an excess reagent because the given moles are greater than the required moles and H_2 is a limiting reagent and it limits the formation of product.

Now we have to calculate the excess moles of N_2 reactant (unreacted gas).

Excess moles of N_2 reactant = 70.49 - 52.2 = 18.29 moles

Now we have to calculate the volume of reactant, measured at STP, is left over.

PV=nRT

where,

P = Pressure of gas at STP = 1 atm

V = Volume of gas = ?

n = number of moles of unreacted gas = 18.29 moles

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

1atm\times V=18.29mole\times (0.0821L.atm/mol.K)\times 273K

V=409.9L

Therefore, the volume of reactant measured at STP left over is 409.9 L

8 0
3 years ago
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