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coldgirl [10]
4 years ago
15

What is a third variable condition that could create the following correlation? The popularity of online job portals is correlat

ed to the number of people changing jobs. A. internet connectivity B. peer pressure C. lots of available jobs D. health benefits E. availability of better technology
Mathematics
2 answers:
Nonamiya [84]4 years ago
7 0

b hope this helps i think

Natasha2012 [34]4 years ago
7 0

Answer:

C lots of available jobs

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Y=2x+8 y=3x+11 using substitution
WITCHER [35]
For substitution this is what answer I got but I don’t know if that’s what your looking for

5 0
3 years ago
Find the value of each variable
aniked [119]

Answer:

Answer d)

a= 10*\sqrt{3} b=5*\sqrt{3}, c=15, and d=5

Step-by-step explanation:

Notice that there are basically two right angle triangles to examine: a smaller one in size on the right and a larger one on the left, and both share side "b".

So we proceed to find the value of "b" by noticing that it the side "opposite side to angle 60 degrees" in the triangle of the right (the one with hypotenuse = 10). So we can use the sine function to find its value:

b=10*sin(60^o)= 10*\frac{\sqrt{3} }{2} = 5*\sqrt{3}

where we use the fact that the sine of 60 degrees can be written as: \frac{\sqrt{3} }{2}

We can also find the value of "d" in that same small triangle, using the cosine function of 60 degrees:

d=10*cos(60^o)=10* \frac{1}{2} = 5

In order to find the value of side "a", we use the right angle triangle on the left, noticing that "a" s the hypotenuse of that triangle, and our (now known) side "b" is the opposite to the 30 degree angle. We use here the definition of sine of an angle as the quotient between the opposite side and the hypotenuse:

sin(30^o)= \frac{b}{a} \\a=\frac{b}{sin(30)} \\a=\frac{5*\sqrt{3} }{\frac{1}{2} } \\a= 10*\sqrt{3}

where we used the value of the sine function of 30 degrees as one half: \frac{1}{2}

Finally, we can find the value of the fourth unknown: "c", by using the cos of 30 degrees and the now known value of the hypotenuse in that left triangle:

c=10*\sqrt{3} * cos(30^o)=10*\sqrt{3} *\frac{\sqrt{3} }{2} \\c= 5*3=15

Therefore, our answer agrees with the values shown in option d)

6 0
3 years ago
An urn contains three white balls and two red balls. The balls are drawn from the urn, oneat a time without replacement, until a
Tpy6a [65]

Answer:

p ( X = 1 ) = 0.6 , p ( X = 2 ) = 0.3 , p ( X = 3 ) = 0.1

Verified

E ( X ) = 1.5

Step-by-step explanation:

Solution:-

- An urn contains the following colored balls:

                       Color                  Number of balls

                       White                            3

                       Red                               2

- A ball is drawn from urn without replacement until a white ball is drawn for the first time.

- We will construct cases to determine the distribution of the random-variable X: The number of trials it takes to get the first white ball.

- We have three following case:

1) White ball is drawn on the first attempt ( X =  1 ). The probability of drawing a white ball in the first trial would be:

              p ( X = 1 ) = ( Number of white balls ) / ( Total number of ball )

              p ( X = 1 ) = ( 3 ) / ( 5 )

2) A red ball is drawn on the first draw and a white ball is drawn on the second trial ( X = 2 ). The probability of drawing a red ball first would be:

      p ( Red on first trial ) = ( Number of red balls ) / ( Total number of balls )

      p ( Red on first trial ) = ( 2 ) / ( 5 )

- Then draw a white ball from a total of 4 balls left in the urn ( remember without replacement ).

   p ( White on second trial ) = ( Number of white balls ) / ( number of balls left )

   p ( White on second trial ) = ( 3 ) / ( 4 )

- Then to draw red on first trial and white ball on second trial we can express:

                p ( X = 2 ) =  p ( Red on first trial ) *  p ( White on second trial )

                p ( X = 2 ) =  ( 2 / 5 ) * ( 3 / 4 )

                p ( X = 2 ) =  ( 3 / 10 )  

3) A red ball is drawn on the first draw and second draw and then a white ball is drawn on the third trial ( X = 3 ). The probability of drawing a red ball first would be ( 2 / 5 ). Then we are left with 4 balls in the urn, we again draw a red ball:

   p ( Red on second trial ) = ( Number of red balls ) / ( number of balls left )

   p ( Red on second trial ) = ( 1 ) / ( 4 )    

 

- Then draw a white ball from a total of 3 balls left in the urn ( remember without replacement ).                  

   p ( White on 3rd trial ) = ( Number of white balls ) / ( number of balls left )

   p ( White on 3rd trial ) = ( 3 ) / ( 3 ) = 1

- Then to draw red on first two trials and white ball on third trial we can express:

                p ( X = 3 ) =  p ( Red on 1st trial )*p ( Red on 2nd trial )*p ( White on 3rd trial )

                p ( X = 3 ) =  ( 2 / 5 ) * ( 1 / 4 ) * 1

                p ( X = 3 ) =  ( 1 / 10 )  

- The probability distribution of X is as follows:

    X          1                  2                      3

p ( X )      0.6               0.3                  0.1

- To verify the above the distribution. We will sum all the probabilities for all outcomes ( X = 1 , 2 , 3 ) must be equal to 1.

          ∑ p ( Xi ) = 0.6 + 0.3 + 0.1

                         = 1 ( proven it is indeed a pmf )

- The expected value E ( X ) of the distribution i.e the expected number of trials until we draw a white ball for the first time:

               E ( X ) = ∑ [ p ( Xi ) * Xi  ]

               E ( X ) = ( 1 ) * ( 0.6 ) + ( 2 ) * ( 0.3 ) + ( 3 ) * ( 0.1 )

               E ( X ) = 0.6 + 0.6 + 0.3

               E ( X ) = 1.5 trials until first white ball is drawn.

8 0
4 years ago
Seven members of a Girl Scout troop report the following individual earnings from their sale of candy: $4, $1, $7, $6, $8, $2, a
Radda [10]

Answer:

(B) the mean is less than the mode and less than the median.

Step-by-step explanation:

Mean, Median, Mode is used to calculate the central tendency of the distribution.

Mean is defined as,

Mean = \dfrac{Sum of all observation}{Total number of observation}\\ \ \ \ \ \ \ \ \ = \dfrac{4+1+7+6+8+2+7}{7}

∴ Mean = 5

Median is the middle observation of the distribution after arranging it in ascending or descending order.

So, arranging distribution in ascending order we get,

$1, $2, $4, $6, $7, $7, $8

Also, a number of observation is 7 which is an odd number.

Hence, Median = (\frac{Number of observation + 1}{2})^{th} term

⇒ Median = (\frac{7 + 1}{2})^{th} term

⇒ Median = 4th term = 6

Mode is the observation which has highest frequency.

Here, only $7 is repeated 2 times.

Hence, Mode = 7.

Hence, we see that Mean < Median < Mode

So, Option (B) is correct i.e. mean is less than the mode and less than the median.

8 0
4 years ago
What is the slope of the line represented by the equation 3z + 4y = 12
garik1379 [7]

Answer: M=  -3/4

Step-by-step explanation:

4 0
3 years ago
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