Question

A spinner is divided into two equal parts, one red and one blue. The set of possible outcomes when the spinner is spun twice is S = {RR, RB, BR, BB}. Let X represent the number of times blue occurs. Which of the following is the probability distribution, PX(x)?

Answer 1

ФThe Answer is A).the first graph i know this is the correct Answer.Ф 

Answer 2

Suppose that the spinner is spun twice. Find the probabilities:

$Pr(X=0),\ Pr(X=1),\ Pr(X=2).$

1. When X=0, blue occurs 0 times. There is one favorable outcome (RR) from four possible. Then

$Pr(X=0)=\dfrac{1}{4}.$

2. When X=1, blue occurs 1 times. There are two favorable outcomes (RB and BR) from four possible. Then

$Pr(X=1)=\dfrac{2}{4}=\dfrac{1}{2}.$

3. When X=2, blue occurs 2 times. There is one favorable outcome (BB) from four possible. Then

$Pr(X=2)=\dfrac{1}{4}.$

At last, the distribution table takes look

$\begin{array}{cccc}x_i &|\ 0 & 1 & 2 \\------& -- &---&--- \\Pr(X=x_i) & \left |\ \dfrac{1}{4} & \dfrac{1}{2} & \dfrac{1}{4}\end{array}$