Answer:
1 - cosΘ
Step-by-step explanation:
using the identity
sin²x + cos²x = 1 , then
sin²x = 1 - cos²x

=
← factor 1 - cos²Θ as a difference of squares
=
← cancel 1 + cosΘ on numerator/ denominator
= 1 - cosΘ
Answer:
16
Step-by-step explanation:
Given the equation,
, let's solve for x as follows,
Subtract 200 from both sides


Subtract 15x from both sides


Divide both sides by -5


1 byte9 Cube root of b^27 = b^27/3 = b^9.
<span>x+y=30.....(1) and x-y=2......(2) so(1)+(2)......x+y+x-y=30+2 so 2x=32...x=16 now apply x=16 in (1) so we get......16+y=30 so .......y=14</span>