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3 years ago

Please help with this question

Mathematics

1 answer:

aleksandr82 [10.1K]3 years ago

5 0

Answer:

D) -9/4

Step-by-step explanation:

please refer to the picture I sent

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3 years ago

Read 2 more answers

Farmer Joogh started with 90 yoys on his farm. Every month, he got 3 more of them. Farmer Dubble started with 21 yoys on her far

Aleonysh [2.5K]

Answer:

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Step-by-step explanation:

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3 years ago

Consider the following set of equations:

guapka [62]

Hello :
<span>A) 2x + 4 = 3x + 1
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3 years ago

What is the constant of proportionality in the equation StartFraction x over y EndFraction = StartFraction 2 over 9 EndFraction?

Vlad [161]

We have been given an equation $\frac{x}{y}=\frac{2}{9}$ . We are asked to find constant of proportionality from our given equation.

We know that two directly proportional equations are in form $y=kx$ ,where y is directly proportional to x and k is constant of proportionality.

Let us rewrite our given equation by cross multiplying as:

$2y=9x$

Now we will divide both sides of equation by 2.

$\frac{2y}{2}=\frac{9x}{2}$

$y=\frac{9}{2}x$

We can see that our equation is in form $y=kx$ and constant of proportionality is $\frac{9}{2}$ .

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3 years ago

Hi there can you please help me with this question please anyone

lorasvet [3.4K]

$11;\ 13;\ 13;\ 13;\ 13;\ 15\\\\\overline{x}=\dfrac{11+13+13+13+13+15}{6}=\dfrac{78}{6}=13\\\\\delta^2=\dfrac{(x_1-\overline{x})^2+(x_2-\overline{x})^2+(x_3-\overline{x})^2+...+(x_n-\overline{x})^2}{n}\\\\\delta^2=\dfrac{(11-13)^2+(13-13)^2+(13-13)^2+(13-13)^2+}{6}$
$\dfrac{+(13-13)^2+(15-13)^2}{6}\\\\\delta^2=\dfrac{(-2)^2+0+0+0+0+2^2}{6}=\dfrac{4+4}{6}=\dfrac{8}{6}=\dfrac{4}{3}$

$standard\ deviation:\\\\\sqrt{\delta^2}=\sqrt{\dfrac{4}{3}}=\dfrac{\sqrt4}{\sqrt3}=\dfrac{2\cdot\sqrt3}{\sqrt3\cdot\sqrt3}=\boxed{\dfrac{2\sqrt3}{3}}\approx\boxed{1.15}$

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4 years ago