Its faster in adding isn't always right when you are multiplying numbers
Let a ∈ A. Then a is some integer that is divisible by 4, so we can write a = 4k for some integer k.
We can simultaneously rewrite a as a = 2•2k, so 2 clearly divides a, which means a ∈ B as well.
Therefore A ⊆ B.
a) n (No. of peoples) = 50
r (No. of prizes) = 3
p(n,r) = p (50,3)
b) n(No. of players)=14
r (No. of players for Batting)=9
c)n(Total applicants)=30
r(tester positions)=4
Answer:
16
Step-by-step explanation:
BODMAS
Brackets first, 2+2 = 4
8÷2 = 4
4 x 4 = 16
Simplify: 40y^3 - 8y^2 + 16y/8 y^2
40y^3 + -8y^2 + 2y^3
Combine terms: 40y^3 + -8y^2 + 2y^3
(40y^3 + 2y^3) + (-8y^2)
Answer: 42y^3 + -8y^2
