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BartSMP [9]
3 years ago
9

Archaeologists want to represent a rectangular dig site on the coordinate grid. Each unit represents 1 m. Three vertices of the

rectangle are A(‚àí6,7) , B(4,7) , and C(4,‚àí4) . Use the point tool to plot these three points, and then plot the fourth vertex of the rectangle. Label the points A, B, C, and D. Then use the segment tool to draw all 4 sides of the rectangle. The archaeologists found artifacts at two locations within the dig site. The point for location 1 is shown on the grid and labeled 1.The coordinates for location 2 are (‚àí2,4) . Plot a point to represent location 2, and then label that point 2. PointSegmentLabel UndoRedoReset
Mathematics
1 answer:
yulyashka [42]3 years ago
3 0
I am to young to help you
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What is the area of a regular hexagon with a distance from its center to a vertex of 1 cm? (Hint: A regular hexagon can be divid
devlian [24]
<h3>Answer:</h3><h3>Exact area = \frac{3}{2}\sqrt{3} square cm</h3><h3>Approximate area = 2.598 square cm</h3>

=================================================

Work Shown:

s = side length of equilateral triangle = 1 cm

A = area of equilateral triangle with side length 's'

A = \frac{\sqrt{3}}{4}*s^2

A = \frac{\sqrt{3}}{4}*1^2

A = \frac{\sqrt{3}}{4}

This is just one of the 6 equilateral triangles (see diagram below)

Multiply by 6 to get the area of all 6 equilateral triangles, or the entire hexagonal area

6*A = 6*\frac{\sqrt{3}}{4}

6A = \frac{3\sqrt{3}}{2}

6A \approx 2.598

4 0
3 years ago
Can you evaluate 6x-3y-3x?
Hunter-Best [27]

Answer:

= 3x - 3y

Step-by-step explanation:

7 0
3 years ago
Find Area of A regular polygon. <br> A square with a side of 5?
Daniel [21]

Area of square is

A=a^2

We have a=5 hence

A=5^2=5\cdot5=\boxed{25}

Hope this helps.

8 0
3 years ago
Graph the points (-3,4) and (1,1). If you drew a line through the points, name three other points that would be on the line. How
Andrej [43]
The easiest way to solve this problem is to find the equation of the line joining these two points, then get the values of the points on this line.

We have first point (x1,y1) = (-3,4) and second point (x2,y2) = (1,1).
The equation of the line is y = mx + c
The slope (m) = (y2-y1) / (x2-x1) = (1-4) / (1--3) = -0.75

Then we will use one of these points to get the value of c as follows:
y = mx + c
1 = -0.75 (1) + c ..............> c = 1.75

The equation of this straight line is:
y = -0.75 x + 1.75

Now to get points on this line, we will assume values for either x or y and calculate the other as follows:
1- For x = 0:
y = -0.75 (0) + 1.75 = 1.75
point is (0,1.75)
2- For y = 0:
0 = -0.75 x + 1.75 ..............> x = 2.334
point is (2.334,0)
3- For x = 2:
y = -0.75(2) + 1.75 = 0.25
point is (2,0.25)
3 0
4 years ago
Find the h.c.f of {x}^{3} + {y}^{3} \: and \: \: {x}^{2} - xy + {y}^{2}x 3 +y 3 andx 2 −xy+y 2 ​
Ahat [919]

Factorize the sum of cubes:

x^3 + y^3 = (x+y) (x^2 - xy + y^2)

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5 0
2 years ago
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