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zheka24 [161]
3 years ago
8

Chlorophenols impart unpleasant taste and odor to drinking water at concentrations as low as 5 mg/m3. They are formed when the c

hlorine dis- infection process is applied to phenol-containing waters. What is the threshold for unpleasant taste and odor in units of (a) mg/L, (b) mg/L, (c) ppmm, and (d) ppbm

Chemistry
1 answer:
trapecia [35]3 years ago
4 0

Answer:

See explaination

Explanation:

Chlorine’s disinfection properties have helped improve the lives of billions of people around the world. Chlorine also is an essential chemical building block, used to make many products that contribute to public health and safety, advanced technology, nutrition, security and transportation.

Please kindly check attachment for the step by step solution of the given problem.

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How many moles in 2.33E25 molecules of NO?
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0.0258 mol <em>Answer</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

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Which factor does not influence stream velocity
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The factor that does not influence stream velocity is DISCHARGE.
Stream velocity refers to the speed with which the water in a stream is flowing. The factors which affect stream velocity include channel size, channel shape, turbulent flow and gradient.
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3 years ago
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Use this diagram to answer the following
mylen [45]

Answer:An atom

Explanation:

Because  molecules more spread out and have things that connnect them and are not bunched up togoether

And Atoms are all packed up like in the picture

Hope this helps!:D

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2 years ago
Solve for x, where M is molar and s is seconds. x=(5.3×103M−2s−1)(0.26M)3
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3 years ago
Calculate the molality, molarity, and mole fraction of FeCl3 in a 29.5 mass % aqueous solution (d = 1.283 g/mL).
faltersainse [42]

Answer:

molality FeCl3= 2.579 molal

molarity FeCl3 = 2.333 M

mol fraction FeCl3 = 0.0444

Explanation:

Step 1: Data given

Mass % = 29.5 %

Density = 1.283 g/mL

Molar mass FeCl3 = 162.2 g/mol

Step 2: Calculate mass solution

Suppose we have 1L = 1000 mL solution

Mass solution = 1.283 g/mL * 1000 mL = 1283 grams

Step 3: Calculate mass FeCl3

Mass FeCl3 = 0.295 * 1283 grams

Mass FeCl3 =  378.485 grams

Step 4: Calculate mass of water

Mass water = 1283 - 378.485 = 904.515 grams

Step 5: Calculate moles FeCl3

Moles FeCl3 = mass FeCl3 / molar mass FeCl3

Moles FeCl3 = 378.485 grams / 162.2 g/mol

Moles FeCl3 = 2.333 moles

Step 6: Calculate moles H2O

Moles H2O = 904.515 grams / 18.02 g/mol

Moles H2O = 50.195 moles

Step 7: Mol fraction FeCl3

Mol fraction FeCl3 = 2.333 / (50.195+2.333)

Mol fraction FeCl3 =   0.0444

Step 8: Calculate molality

Molality = moles FeCl3 / mass H2O

Molality = 2.333 moles / 0.904515 kg

Molality = 2.579 molal

Step 9: Calculate molarity

Molarity = moles / volume

Molarity FeCl3 = 2.333 moles / 1 L

Molarity FeCl3 = 2.333 M

8 0
3 years ago
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