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attashe74 [19]
3 years ago
10

What can you say about the forces between the particles of these gases)​

Chemistry
1 answer:
denis-greek [22]3 years ago
8 0

Answer:

Gas – In a gas, particles are in continual straight-line motion. The kinetic energy of the molecule is greater than the attractive force between them, thus they are much farther apart and move freely of each other. In most cases, there are essentially no attractive forces between particles.

Explanation:hopes this helps:)

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Please help me with this chem question, I’ll mark you brainiest if it’s right. There’s multiple answers for this one.
Kazeer [188]

Answer:

Option A. KCl (aq)

Option D. Mg(OH)₂(s

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

MgCl₂(aq) + KOH(aq) —>

In solution, MgCl₂(aq) and KOH(aq) will dissociate as follow:

MgCl₂(aq) —> Mg²⁺(aq) + 2Cl¯(aq)

KOH(aq) —> K⁺(aq) + OH¯(aq)

MgCl₂(aq) + KOH(aq) —>

Mg²⁺(aq) + 2Cl¯(aq) + 2K⁺(aq) + OH¯(aq) —> 2K⁺(aq) + 2Cl¯(aq) + Mg(OH)₂ (s)

MgCl₂(aq) + KOH(aq) —> 2KCl (aq) + Mg(OH)₂(s)

Thus, the products of the above reaction are: KCl(aq) and Mg(OH)₂(s)

Thus, option A and D gives the correct answer to the question.

8 0
2 years ago
What is the maximum amount in moles of P2O5 that can theoretically be made from 235 g of P4 and excess oxygen?
Lady_Fox [76]
The correct answer would be 3.8mol
5 0
3 years ago
How to make a sugar cube dissolve more quickly in water?
Vesna [10]
Heat the water up a little
3 0
3 years ago
Aqueous solutions of Na2CO3 and Ca(NO3)2, 0.10 M each, are combined. A white precipitate is observed in the container after mixi
anzhelika [568]

The question is incomplete. Here is the complete question.

Aqueous solutions of Na_{2}CO_{3} and Ca(NO_{3})_{2}, 0.10 M each, are combined. A white precipitate is observed in the container after mixing. he precipitate is filtered andcarefully rinsed with distilled water to remove other ions. A sample of the precipitate is added to 100 mL of 0.1 M NaCl. A second sample of the precipitate is then added to 100 mL of 0.1 M HCl. What would be observed in each case?

                 Observation upon                                         Observation upon

               addition of precipitate                                  addition of precipitate

                      to NaCl(aq)                                                       to HCl(aq)

(A)     additional precipitates forms                        no visible reaction occurs

(B)     no visible reaction occurs                            gas is produced and some                                                                                        precipitate dissolves

(C)     no visible reaction occurs                             no visible reaction occurs

(D)     additional precipitates forms                       gas is produced and some

                                                                                    precipitate dissolves

Answer: (B) No visible reaction occurs; Gas is produced and some precipitate dissolves

Explanation: When aqueous solutions of Na_{2}CO_{3} and Ca(NO_{3})_{2} are combined, it reacts according to the following balanced equation:

Na_{2}CO_{3}+Ca(NO_{3})_{2} → CaCO_{3}_{(s)}+2NaNO_{3}_{(aq)}

forming calcium carbonate (CaCO_{3}), which, as it is insoluble in water, precipitates as a solid of the color white. This process is <u>Precipitation</u> and this reaction is a <u>Precipitation</u> <u>Reaction</u>.

When calcium carbonate reacts with NaCl it produces:

CaCO_{3}+2NaCl → CaCl_{2}+Na_{2}CO_{3}

Now, calcium chloride is an inorganic compound very soluble in water, so, in this reaction, there are no precipitate and <u>no visible reaction occurs</u>.

When CaCO_{3} reacts with hydrochloridric acid, the balanced reaction is

CaCO_{3}+2HCl → CaCl_{2}+H_{2}CO_{3}

which, also produces calcium chloride and carbonic acid.

Both are soluble in water but, when carbonic acid is in an "aqueous state", carbonic acid, it dissociates, forming carbon dioxide and water. Therefore, <u>gas is produced and some precipitate dissolves</u>.

In conclusion, sentence B is the correct alternative.

5 0
3 years ago
Given the equation C3H8(g) + O2(g) = CO2(g) + H2O(g) and that the enthalpies of formation for H2O(g) = -241.8 kJ/mol, CO2(g) = -
kari74 [83]

Answer: 72.4 kJ/mol

Explanation:

The balanced chemical reaction is,

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(l)  \Delta H=-2220.1kJ/mol

The expression for enthalpy change is,

\Delta H=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

\Delta H=[(n_{CO_2}\times \Delta H_{CO_2})+(n_{H_2O}\times \Delta H_{H_2O})]-[(n_{O_2}\times \Delta H_{O_2})+(n_{C_3H_8}\times \Delta H_{C_3H_8})]

where,

n = number of moles

\Delta H_{O_2}=0 (as heat of formation of substances in their standard state is zero

Now put all the given values in this expression, we get

-2220.1=[(3\times -393.5)+(4\times -241.8)]-[(5\times 0)+(1\times \Delta H_{C_3H_8})]

\Delta H_{C_3H_8}=72.4kJ/mol

Therefore, the heat of formation of propane is 72.4 kJ/mol

7 0
2 years ago
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