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Dahasolnce [82]
3 years ago
5

Need help Converting 4.82 mmol to grams. Compound is KMn04/CuSO4*5H20

Chemistry
1 answer:
allsm [11]3 years ago
6 0

Answer:

Mass of the substance, grams

86.8

Molar mass of the substance

18.0

Molar mass details

2.0160 H (2*1.008) + 15.9990 O (1*15.999)

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PLEASE HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
serg [7]

Answer:

ITS B

Explanation:

MY CONSCIOUS MIND IS TELLING ME

6 0
2 years ago
Fe2O3 +3CO--2Fe+3CO2 .identify the substance oxidized ,reduced and oxidizing agent and reducing agent​
VikaD [51]

Answer:

Oxidized : CO

Reduced: Fe

Oxidizing agent: Fe2O3

Reducing agent: CO

Explanation:

Loss of electrons is oxidation while gaining of electrons is reduction.

CO is a reducing agent, Fe2O3 is an oxidizing agent.

Each carbon atom is oxidized in CO. CO is the reducing agent

Each Fe atom in FeO3 is reduced. FeO3 is the oxidizing agent

6 0
3 years ago
In general, the ________ of a simple machine is the ratio of the distance over which the force is applied to the distance over w
madreJ [45]
The answer that best fits the blank provided above is MECHANICAL.
7 0
3 years ago
A gas has a volume of 25 ml, at a pressure of 1 atmosphere (1 atm). Increase the volume to 125 ml and the temperature remains co
vekshin1

<h2>0.2 atm </h2>

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2 \\

Since we're finding the new pressure

P_2 =  \frac{P_1V_1}{V_2}  \\

We have

P_2  =  \frac{25 \times 1}{125}  =  \frac{25}{125}   = \frac{1}{5}  = 0.2 \\

We have the final answer as

<h3>0.2 atm</h3>

Hope this helps you

8 0
3 years ago
A ballon begins at sea level at 1 atm. It rises in the atmosphere to where the pressure is lower, to where the pressure is .75 a
maxonik [38]

Answer:

Original volume=3L

Explanation:

Assuming the gas in the ballon is ideal and the temperature does not vary with height  we have the gas law as

PV=nRT

Here RHS is constant in both the conditions which means

PV=constant

Given P1=1 atm V1=V  P2=0.75atm V2=4L

P1V1=P2V2

1*V=0.75*4

V=3L

The initial volume of the gas is 3L

4 0
3 years ago
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