Answer:
.055 mol/L
Explanation:
Henry's Law is about solubility of a gas in a liquid which is dependent on the partial pressure of gas above the liquid . According to it
C = k P where C is concentration of gas in the liquid , k is henry's constant and P is partial pressure of the gas .
Given k = .159 mol/L.atm
P = 265 mm of Hg
= 265 / 760
= .34868 atm
C = kP
= .159 x .34868
= .055 mol/L
Because they are different elements have different number of protons and neutrons........ I guessed do not trust me...
<h2><em>hope</em><em> it</em><em> helps</em></h2>
Answer:
172 g Al
Step-by-step explanation:
We know we will need a balanced equation with masses and molar masses, so let’s <em>gather all the information</em> in one place.
M_r: 26.98 101.96
4Al + 3O₂ ⟶ 2Al₂O₃
m/g: 325
(a) Calculate the <em>moles of Al₂O₃
</em>
n = 325 g Al₂O₃ × 1 mol Al₂O₃ /39.10 g Al₂O₃
n = 3.188 mol Al₂O₃
(b) Calculate the <em>moles of Al
</em>
The molar ratio is (4 mol Al/2 mol Al₂O₃)
n = 3.188 mol Al₂O₃ × (4 mol Al/2 mol Al₂O₃)
n = 6.375 mol Al
(c) Calculate the <em>mass of Al</em>
m = 6.375 mol Al × (26.98 g Al/1 mol Al)
m = 172 g Al
Note: The answer can have only <em>three</em> significant figures because that is all you gave for the mass of Al₂O₃.
