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Delvig [45]
3 years ago
14

£11000 of 3.9% compound interest of 3 years ?

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
4 0
Compound Interest

A = P(1 + r)^(n)

A = Amount, r = rate per year = 3.9% = 3.9/100 = 0.039, n = year = 3 

A = P(1 + r)^(n)

A = 11000(1 + 0.039)^(3)

A = 11000(1.039)^(3)      use calculator

A ≈ 12337.85

Compound Interest = A - P = 12337.85 - 11000 = 1337.85

So at the end of 3 years the Amount is ≈ £12 337.85 and the compound interest is ≈ £1 337.85 

Hope this helps.
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