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aleksklad [387]
2 years ago
9

Helppp!

Mathematics
2 answers:
Vika [28.1K]2 years ago
7 0
The answer to this question is C.5:6:10
ki77a [65]2 years ago
3 0
C. 5:6:10 Explanation: since they all have a common dividend of 7, u just have to divide all of them by 7 :)
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Listed below are pulse rates​ (beats per​ minute) from samples of adult males and females. Find the mean and median for each of
gulaghasi [49]

Answer:

Male: Median: 64.5 and the mean is 70.6

Female: median: 83 and mean is: 79.93

Step-by-step explanation:

For median, you place all of the numbers from lowest to highest, and then find the number in the middle.

For Mean, add up all the numbers, then divide by the amount of numbers there.

For example.

30/5= 6

3 0
2 years ago
If there are 32 boys and 56 girls in a room, fill out all of the possible ratios of boys to girls that could be made.
leonid [27]

Answer:

4/7

Step-by-step explanation:

32/56=4/7

3 0
3 years ago
Read 2 more answers
Which zero pair could be added to the function f(x)=x^2+12x+6 so that the function can be written in vertex form?
andrew11 [14]
<span>f(x) = x</span>² <span>+ 12x + 6  </span>→ y = x² + 12x + 6<span>

Let us convert the standard form into vertex form.

1) Complete the squares. Isolate x</span>² and x terms.
<span>y - 6 = x</span>² + 12x
<span>
2) Create the perfect square trinomial. Whatever number is added on one side must also be added on the other side. 

y - 6 + 36 = x</span>² + 12x + 36<span>
y + 30 = (x + 6)</span>²
<span>y = (x + 6)</span>² - 30  ← Vertex form
<span>
To check:

y = (x + 6) (x + 6) - 30
y = x</span>² + 6x + 6x + 36 - 30
<span>y = x</span>² + 12x + 6<span>

The zero that could be added to the given function is 36, -36</span>
4 0
3 years ago
A building has a height of 100ft and a length of 100ft. An architect wants to add to the building by doubling the length of the
skelet666 [1.2K]
That would be 200ft sir
5 0
3 years ago
3 questions in 1
MrRissso [65]

Answer:

1. D. 20, 30, and 50

2. A. 86

3. B. 94

Step-by-step explanation:

1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.

The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.

Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.

Thus:

Q1 = (85 + 87)/2 = 86

Q3 = (93 + 95)/2 = 94

IQR = Q3 - Q1 = 94 - 86

IQR = 8

Outliers in the data set are data values below the lower limit or above the upper limit.

Let's find the lower and upper limit.

Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74

The data values below the lower limit (74) are 20, 30, and 50

Let's see if we have any data value above the upper limit.

Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106

No data value is above 106.

Therefore, the only outliers of the data set are:

D. 20, 30, and 50

2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.

Thus:

Q1 = (85 + 87)/2 = 86

3. Q3 = (93 + 95)/2 = 94

3 0
2 years ago
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