Answer:
Explanation:
The difference in time will be due to travel through atmosphere where speed of light slows down. If t be the thickness of atmosphere and c be the speed of light in space and μ be the refractive index of atmosphere difference in travel time will be as follows .
difference = \frac{2t\mu }{c}-\frac{2t }{c}
=\frac{2t}{c }\left ( 1-\mu \right )
Now t = 40 x 10³m ,μ = 1.000293 , c = 3 x 10⁸.
difference =\frac{2t\mu }{c}-\frac{2t }{c}
=\frac{2t}{c }\left ( \mu -1 \right )\\
=\frac{ 2\times 40\times 10^3}{3\times10^3 }\left ( 1.000293-1 \right )\\
=7.81\times 10^{-3}
s
Answer:
<h2>The answer is 2.5 m/s²</h2>
Explanation:
The acceleration of an object given it's velocity and time taken acting on it can be found by using the formula

From the question
time = 4 s
velocity = 10 m/s
So we have

We have the final answer as
<h3>2.5 m/s²</h3>
Hope this helps you
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