The combined momentum of the passengers is 5000 kgm/s.
<h3>Combined momentum of the passenger</h3>
The combined momentum of the passengers is calculated as follows;
P = mv1 + mv2
where;
- m is mass of the passengers
- v1 is velocity of the first passenger
- v2 is velocity of the second passenger
P = m(v1 + v2)
P = 5000(-1 + 2)
P = 5000 kgm/s
Thus, the combined momentum of the passengers is 5000 kgm/s.
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Answer:
r = 102.43 m
Explanation:
Newton's second law for this case is
F = ma
Where the acceleration is centripetal
a = v² / r
r = v² / a
They indicate that the radial acceleration is 8.45 g
r = v² / 8.45 g.
r = 92.1² / 8.45 9.8
r = 102.43 m
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