Answer:
the answer will be 24.40 ohms law
Explanation:
Answer: Option (C) is the correct answer.
Explanation:
Sodium has atomic number 11 and its electronic distribution is 2, 8, 1. Whereas chlorine has atomic number 17 and its electronic configuration is 2, 8, 7.
Therefore, we can see that sodium has one extra electron and chlorine has deficiency of one electron.
So, in order to complete their octet sodium will give its one valence electron to the chlorine atom. Hence, there is exchange of electrons and thus it will result in the formation of ionic bond.
Thus, we can conclude that in sodium chloride electron movement is related to the bonding as electrons exchange creating ions to form an ionic bond by electrostatic attraction.
We Know, F = m.a
Here, m = 2 Kg
& a = 2 m/s²
Substitute for it,
F = 2*2 Kgm/s²
F = 4 Kgm/s²
Answer:
The magnitude of the electric field equal to 2.40 N/C at 1.1537m from the wire.
Explanation:
using Guass law,
(guessing that a cylinder of radius r and length L around wire such that wire is at centre )
E. A = qin / e0
E ( 2πr L ) = (1.56 x 
x L) / (8.85 x 
)
E = (1.56 x ) / (2πr x 8.85 x )
so 2.40 = (1.54 x ) / (2πr x 8.85 x )
2.40 (6.284r) = 0.174 x 10²
15.0816r = 17.4
r = 1.1537m
