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andrew11 [14]
3 years ago
9

You measure a watch's hour and minute hands to be 7.4 mm and 12.1 mm long, respectively. Part A In one day, by how much does the

distance traveled by the tip of the minute hand exceed the distance traveled by the tip of the hour hand?
Physics
1 answer:
pychu [463]3 years ago
3 0

Answer:

109.385m

Explanation:

In 1 day, the hour hand travels 2 circles, or 4π rad in angular. The distance it travels is its angle times the radius

7.4 * 4π = 93 mm

In 1 day, the minute hand travels 24*60 = 1440 circles, or 1440 * 2π = 2880π rad in angular. The distance it travels is

12.1 * 2880π = 109478 mm

So the distance traveled by the tip of the minute hand that exceed the distance traveled by the tip of the hour hand is

109478 - 93 = 109385 mm or 109.385 m

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A circular loop of wire of area 10 cm^2 carries a current of 25 A. At a particular instant, the loop lies in the xy-plane and is
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The magnetic dipole moment of the current loop is  0.025 Am².

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<h3>What is magnetic dipole moment?</h3>

The magnetic dipole moment of an object, is the measure of the object's tendency to align with a magnetic field.

Mathematically, magnetic dipole moment is given as;

μ = NIA

where;

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μ = (1) x (25 A) x (0.001 m²)

μ = 0.025 Am²

The magnetic torque on the loop is calculated as follows;

τ = μB

where;

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B = √(0.002² + 0.006² + 0.008²)

B = 0.01 T

τ = μB

τ =  0.025 Am² x 0.01 T

τ = 2.5 x 10⁻⁴  Nm

Thus, the magnetic dipole moment of the current loop is determined from the current and area of the loop while the magnetic torque on the loop is determined from the magnetic dipole moment.

Learn more about magnetic dipole moment here: brainly.com/question/13068184

#SPJ1

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1 year ago
HELP WILL MEDAL!!!! HELP
steposvetlana [31]
Here try this. The pic is the answer

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