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AlexFokin [52]
3 years ago
13

4. Where can we use compost?​

Physics
1 answer:
Oksanka [162]3 years ago
6 0
You can use compost on your soil as a soil amendment.
You might be interested in
6. A 0.09 kg arrow hits a target at 22 m/s and penetrates 4 cm before stopping.
tatyana61 [14]
A ) v = v o - a t
0 = 22 - a · t
a · t = 22
d = v o · t - a t²/2
0.04 = 22 t - 22 t / 2
0.04 = 11 t
t = 0.04 : 11 = 0.003636 s
a = 22 / t
a = 6050 m/s²
F = m · a = 0.09 kg · 6050 m/s²
F ( target→arrow) = - 544.5 N
b ) F ( arrow→target ) = 544.5 N
c )  If the speed was doubled:  v = 44 m/s;
F = a m
a = 6050 m/s²
a · t = 44
t = 6050 : 0.04
t = 0.007272 s
d = 44 t - 44 t/2 = 22 t
d = 22 · 0.007272
d = 0.16 m = 16 cm
8 0
3 years ago
5. A 5.0 kg object accelerates uniformly from rest for 5.0 s and reaches a final velocity of 20.0 m/s. At 3.0 s, what is the obj
irina [24]

Answer:

jack JACKKK

Explanation:

OK YAHHHHH SO DO THIS

3 0
4 years ago
1. At the synaptic terminal, voltage-gated ______________ channels open, thereby stimulating the synaptic vesicles to release th
Sergeeva-Olga [200]

Ion

<u>Explanation:</u>

At the synaptic terminal, voltage-gated ion channels open, thereby stimulating the synaptic vesicles to release the neurotransmitters by exocytosis.

These ion channels are the signaling molecules in neurons. They are the transmembrane proteins that form ion channels. The membrane potential changes the conformation of the channel proteins that regulates their opening and closing. These channels play an important role in neurotransmitter release in presynaptic nerve endings.

For example - Ca²⁺ gated ion channel.

4 0
3 years ago
A 4.00-kg model rocket is launched, expelling 64.0 g of burned fuel from its exhaust at a speed of 675 m/s. What is the velocity
olga_2 [115]

Answer:

The velocity of the rocket is 7.8 m/s

Explanation:

3 0
3 years ago
A current of 200 mA through a conductor converts 40 joules of electrical energy into heat in 30 second
Komok [63]

Answer:

V = 6.65 [volt]

Explanation:

First, we must calculate the power by means of the following equation, where the voltage is related to the energy produced or consumed in a given time.

P=E/t\\P = 40/30\\P = 1.33[s]

Using the power we can calculate the voltage, by means of the following equation that relates the voltage to the current.

P=V*I

where:

V = voltage [Volts]

I = current = 200 [mA] = 0.2 [A]

V = 1.33/0.2\\V = 6.65 [volt]

8 0
3 years ago
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