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amid [387]
3 years ago
11

read The question and give Me The answers for number 19 This is a Tough one it wants Me To click on The graph

Mathematics
1 answer:
shtirl [24]3 years ago
7 0

Answer:

(0, 5)

Step-by-step explanation:

At the time the ball is thrown time t = 0

The corresponding height at t = 0 is 5 ft

This is the point (0, 5) on the graph

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What is −30−6r= -36 ?
Nadya [2.5K]

-30-6r=36

We move all terms to the left:

-30-6r-(36)=0

We add all the numbers together, and all the variables

-6r-66=0

We move all terms containing r to the left, all other terms to the right

-6r=66

r=66/-6

r=-11

7 0
3 years ago
Read 2 more answers
What is 2a +16 what does that =
kirill115 [55]
A will equal 8. can i get a brainliest plz
7 0
3 years ago
What is the radius of a circle in which a 30 degrees arc is 2 inches long
igomit [66]

arc length = pi /180 * angle in degree * radius

2 = pi/180 * 30 *r

2 = pi/6 *r

multiply by 6/pi

12/pi =r

3.819718634 =r

Answer: r =3.82 inches


6 0
3 years ago
1-What is the sum of the series? ​∑j=152j​ Enter your answer in the box.
tangare [24]

Answer:

Please see the Step-by-step explanation for the answers

Step-by-step explanation:

1)

∑\left \ {{5} \atop {j=1}} \right. 2j

The sum of series from j=1 to j=5 is:

∑ = 2(1) + 2(2) + 2(3) + 2(4) + 2(5)

  =  2 + 4 + 6 + 8 + 10

∑ = 30

2)

This question is not given clearly so i assume the following series that will give you an idea how to solve this:

∑\left \ {{4} \atop {k=1}} \right. 2k²

The sum of series from k=1 to j=4 is:

∑ = 2(1)² + 2(2)² + 2(3)² + 2(4)²

  = 2(1) + 2(4) + 2(9) + 2(16)

  =  2 + 8 + 18 + 32

∑ = 60

∑\left \ {{4} \atop {k=1}} \right. (2k)²

∑ = (2*1)² + (2*2)² + (2*3)² + (2*4)²

  = (2)² + (4)² + (6)² + (8)²

  = 4 + 16 + 36 + 64

∑ = 120

∑\left \ {{4} \atop {k=1}} \right. (2k)²- 4

∑ = (2*1)²-4 + (2*2)²-4 + (2*3)²-4 + (2*4)²-4

  = (2)²-4 + (4)²-4 + (6)²-4 + (8)²-4

  = (4-4) + (16-4) + (36-4) + (64-4)

  = 0 + 12 + 32 + 60

∑ = 104

∑\left \ {{4} \atop {k=1}} \right. 2k²- 4

∑ = 2(1)²-4 + 2(2)²-4 + 2(3)²-4 + 2(4)²-4

  = 2(1)-4 + 2(4)-4 + 2(9)-4 + 2(16)-4

  = (2-4) + (8-4) + (18-4) + (32-4)

  = -2 + 4 + 14 + 28

∑ = 44

3)

∑\left \ {{6} \atop {k=3}} \right. (2k-10)

∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)  

  = (6-10) + (8-10) + (10-10) + (12-10)

  = -4 + -2 + 0 + 2  

∑ = -4

4)

1+1/2+1/4+1/8+1/16+1/32+1/64

This is a geometric sequence where first term is 1 and the common ratio is 1/2 So

a = 1

This can be derived as

1/2/1 = 1/2 * 1 = 1/2

1/4/1/2 = 1/4 * 2/1 = 1/2

1/8/1/4 = 1/8 * 4/1  = 1/2

1/16/1/8 = 1/16 * 8/1  = 1/2

1/32/1/16 = 1/32 * 16/1  = 1/2

1/64/1/32 = 1/64 * 32/1  = 1/2

Hence the common ratio is r = 1/2

So n-th term is:

ar^{n-1} = 1(\frac{1}{2})^{n-1}

So the answer that represents the series in sigma notation is:

∑\left \ {{7} \atop {j=1}} \right. (\frac{1}{2})^{j-1}

5)

−3+(−1)+1+3+5

This is an arithmetic sequence where the first term is -3 and the common difference is 2. So  

a = 1

This can be derived as

-1 - (-3) = -1 + 3 = 2

1 - (-1) = 1 + 1 = 2

3 - 1 = 2

5 - 3 = 2

Hence the common difference d = 2

The nth term is:

a + (n - 1) d

= -3 + (n−1)2

= -3 + 2(n−1)

= -3 + 2n - 2

= 2n - 5

So the answer that represents the series in sigma notation is:

∑\left \ {{5} \atop {j=1}} \right. (2j−5)

6 0
3 years ago
The distance between two locations, A and B, is calculated using a third location C at a distance of 15 miles from location B. I
Jobisdone [24]
We will first calculate ∠A:
∠∠A = 180° - ( 105° + 20 ° ) = 180° - 125° = 55°
Then we will use the Sine Law:
15 / sin 55° = AB / sin 20°
15 / 0.81915 = AB / 0.342
AB · 0.81915 = 15 · 0.342
AB · 0.81915 = 5.13
AB = 5.13 : 0.81915
AB = 6.26 ≈ 6.3 miles
Answer: The distance between the locations A and B is 6.3 miles.
4 0
3 years ago
Read 2 more answers
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