Answer is: <span>the molarity of the diluted solution 0,043 M.
</span>V(NaOH) = 75 mL ÷ 1000 mL/L = 0,075 L.
c(NaOH) = 0,315 M = 0,315 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,075 L · 0,315 mol/L.
n(NaOH) = 0,023625 mol.
V(solution) = 0,475 L + 0,75 L.
c(solution) = 0,023625 mol ÷ 0,550 L.
c(solution) = 0,043 mol/L.
Answer:
4 moles
Explanation:
= 
= 2 (moles)
CH4 + 2O2 → CO2 + 2H2O
1 : 2 : 1 : 2
2 (moles)
⇒ 
= 2 × 2 ÷ 1 = 4 (moles)
C6H10O5 (6 Carbon, 10 Hydrogen and 5 Oxygen)
Answer:
There is 541.6 grams of calcium carbonate produced from 5.11 moles
Explanation:
Step 1: Data given
Number of moles of sodium carbonate ( Na2CO3) = 5.11 moles
Molar mass of sodium Carbonate:
⇒ Molar mass of Sodium = 22.99 g/mole
⇒ Molar mass of Carbon = 12.01 g/mole
⇒ Molar mass of Oxygen = 16 g/mole
Molar mass of Na2CO3 = 2* 22.99 + 12.01 + 3*16 = 105.99 g/mole
Step 2: Calculate mass of 5.11 moles of sodium carbonate
mass = number of moles of sodium carbonate * Molar mass of sodium carbonate
mass = 5.11 moles * 105.99 g/moles = 541.6 grams ≈ 542 grams
There is 541.6 grams of calcium carbonate produced from 5.11 moles Na2CO3
