Answer:
The final angular speed is 0.223 rad/s
Explanation:
By the conservation of angular moment:
ΔL=0
L₁=L₂
L₁ is the initial angular moment
L₂ is the final angular moment
L₁ is given by:
As the door is at rest its angular moment is zero and the angular moment of mud can be considered as a point object, then:
where
r is the distance from the support point to the axis of rotation (the mud hits at the center of the door; r=0.5 m)
v is the speed
m is the mass of the mud
L₂ is given by:
ωf is the final angular speed
The moment of inertia of the door can be considered as a rectangular plate:
M is the mass of the door
W is the width of the door
The moment of inertia of the mud is:
Hence,
Answer:
Nuclear Fusion
Explanation:
Nuclear fusion is the nuclear reaction in which two lighter nucleus combine to form a larger more stable nucleus with the release of energy.
²₁H + ¹₁H ⇒ ³₂He + energy
In this case, a hydrogen atom reacts with a deuterium atom to produce a helium atom and energy.
Since two smaller atoms combine to produce a larger atom, nuclear fusion occurs.
Newton's second law applies. That is,
F=ma, F = Wall force on the object, m = mass of the object, a = Deceleration = Δv/t = (6-8)/2 = -1 m/s
F = 1.2*1 = 1.2 N
Given :
A 12,500 kg railroad freight car travels on a level track at a speed of 5.2 m/s.
It collides and couples with a 22,600 kg second car, initially at rest and with brakes released.
To Find :
The speed of the two cars after collision.
Solution :
It is given that car couples with each other. So speed of both the cars after collision is same. Let, it be v.
Applying conservation of momentum, we get :
Therefore, the speed of the two cars after collision is 1.85 m/s.