<span>a. less biomass
b. more biomass
c. more broad-leaf trees
d. locations near the equator
i would say c
</span>
20m/s, honestly I have know idea what the asnwer is but if i had to guess, this would be my answer.
Answer:
Reaction force = Weight
the force exerted by A on B is equal.
M1a = M2a
Explanation: I think the answer is right if wrong message me.
We have that the speed over the ground of a mosquito flying 2 m/s relative to the air against a 2 m/s headwind is
X=0m/s
From the question we are told that
mosquito flying 2 m/s
against a 2 m/s headwind
Generally
The speed over the ground is the Flight Speed minus resistance speed
Generally the equation for the speed over the ground is mathematically given as
X=Flight Speed-resistance speed
Therefore
X=2-2
X=0m/s
For more information on this visit
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The intention is to determine whether the cables will resist the tension or will break.
There are three tensions
Applyng Newton's Second Law to the student, the tension of the only cable that holds the student has to equal his weight,
T = weight = m*g = 160 lbs / 2.2046 lbs/kg * 9.8 m/s=711 N
Now apply Newton's Second Law to the joint of the cables
There you have that the equilibrium of forces leads to that the sum of the up-components of the other two cables = the tension T just found, i.e. 711 N.
Now find the up-components of the tensions of other two cables:
sin 39 = T_1up / T_1 => T_1up = T_1*sin(39)
sin 55 = T_2up / Ts => T_2up = T_2*sin(55)
Total up tension = T_1*sin(39) + T_2*sin(55)
Newton's second law => total up tension = tension of the cable that holds the student
T_1*sin (39) + T_2*sin(55) = 711 N [equation 1]
Now find the equation from the horizontal equilibrium.
Horizontal-components fo the tension of the other two cables
cos 39 = T_1 left / T_1 => T_1 left = T_1*cos(39)
cos 55 = T_2 right / T_2=> T_2 right = T_2*cos(55)
Second Newton's Law and non movement => left-component = right component.
T_1 * cos(39) = T_2 cos(55) [equation 2]
Equation 1 and equation 2 form a systems of two equations with two variables (T_1 and T_2).
When you solve it you find:
T1 = 711 / [sin(39) + tan(55)*cos(39)] = 711 / 1.739 = 408.9 N
T_2 = cos (39)*408.9 / cos (55) = 553. 9 N
Therefore this cable will break because the tension calculated exceeds 500 N.
