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Whitepunk [10]
2 years ago
10

Partial charges will exist on each atom when a bond exists between two atoms with different electronegativities. Since the atom

with a higher electronegativity will have a stronger ability to attract electrons, it will have a partial _________ charge. The atom with a lower electronegativity will have an equal and opposite _________ charge. As the difference in electronegativity increases, the resulting magnitudes of the partial charges will ___________.
Chemistry
1 answer:
lana66690 [7]2 years ago
7 0

Answer:

negative, positive, increase

Explanation:

From the given question,  

During the formation of bond, between two atoms with difference between their electronegativity-

  • The more electronegative atom, will pull the electrons towards itself , and hence acquires a partial negative charge,

And,

  • The less electronegative atom, will acquire a partial positive charge.
  • The more the difference between the electronegativity of the atoms, the more would be the magnitude of partial charge.
  • And, the less would be the difference between the electronegativity of the atoms, the lesser would be the magnitude of partial charge.
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Every 2 million years the amount is halved
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Given the formula representing a compound: what is a chemical name of this compound? 2-pentene 2-pentyne 3-pentene 3-pentyne
Aleks [24]
The question is incomplete. Complete question is attached below.
..........................................................................................................................

Correct Answer: <em>Option 1) 2-pentene</em>

Reason:
Following are the IUPAC rules for naming the compound
1) Select the longest carbon chain. In present case longest carbon chain has 5 carbon atom. Hence, it is a pentane derivative.
2) In case of alkene, replace 'e' of alkane by 'ene'
3) Give lowest number to function group. In present case, it is double bond.

Applying above rules, the IUPAC name of compound is 2-pentene

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9.Out of the following which is a poly atomic molecule. (H2, CI 2.03.)​
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3 0
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28) Consider a 21.0 mL sample of pure lemon juice with a citric acid (H3C6H5O7) concentration of 0.30M. a. How many moles of cir
Damm [24]
<h3>#a. Answer:</h3>

0.0063 mole

<h3>Solution and explanation:</h3>

We are given 21.0 mL citric acid with a concentration of 0.30 M

Part a requires we calculate the number of moles of citric acid.

We need to know how to calculate the concentration of a solution;

Concentration or molarity = Number of moles ÷ Volume of the solution

Thus;

Number of moles = Concentration × Volume

Hence;

Moles = 0.30 M × 0.021 L

         = 0.0063 mole

<h3>#b. Answer</h3>

1.21 g citric acid

<h3>Solution</h3>

Part B

We are required to calculate the mass of citric acid in the sample

Number of moles of a compound is calculated by dividing its mass by its molar mass.

Molar mass of Citric acid = 192.124 g/mol

Moles of citric acid = 0.0063 mole

But; Mass = Number of moles × Molar mass

Mass of citric acid = 0.0063 mol × 192.124 g/mol

                             = 1.21 g citric acid

<h3>#c. Answer</h3>

4.167 mL

<h3>Solution:</h3>

Part C

We are required to determine the initial volume before dilution;

We have;

Initial concentration (M1) = 0.30 M

Final volume (V2) = 250 mL or 0.25 L

Final concentration (M2) = 0.0050 M

Using the dilution formula we can get the initial volume;

Therefore, since; M1V1 =M2V2

V1 = M2V2÷M1

   = (0.0050 × 0.25)÷ 0.30

   = 0.004167 L or

   = 4.167 mL

Therefore, the initial volume of the solution is 4.167 mL

8 0
3 years ago
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