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Whitepunk [10]
3 years ago
10

Partial charges will exist on each atom when a bond exists between two atoms with different electronegativities. Since the atom

with a higher electronegativity will have a stronger ability to attract electrons, it will have a partial _________ charge. The atom with a lower electronegativity will have an equal and opposite _________ charge. As the difference in electronegativity increases, the resulting magnitudes of the partial charges will ___________.
Chemistry
1 answer:
lana66690 [7]3 years ago
7 0

Answer:

negative, positive, increase

Explanation:

From the given question,  

During the formation of bond, between two atoms with difference between their electronegativity-

  • The more electronegative atom, will pull the electrons towards itself , and hence acquires a partial negative charge,

And,

  • The less electronegative atom, will acquire a partial positive charge.
  • The more the difference between the electronegativity of the atoms, the more would be the magnitude of partial charge.
  • And, the less would be the difference between the electronegativity of the atoms, the lesser would be the magnitude of partial charge.
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Answer:- Heat lost by the metal is 279.45 cal.

Solution:- This type of problems are solved by using the concept, heat given = - heat taken

Metal temperature is decreasing from 45.00 degree C to 11.08 degree C. It means the heat is lost by the metal and this heat lost by metal is gained by water and the calorimeter to raise their temperature.

the equation we use is, q=mc\Delta T .

where, q is the heat energy, m is mass, c is specific heat and \Delta T is change in temperature.

Combined mass of calorimeter and water is 250.0 g and the specific heat is \frac{1.035cal}{g.^0C} .

\Delta T  for calorimeter and water (combined) = 11.08 - 10.00 = 1.08 degree C

\Delta T  for metal = 11.08 - 45.00 = -33.92 degree C

let's plug in the values in the above equation and calculate heat gained by combined system.

q=250.0g*\frac{1.035cal}{g.^0C}*1.08^0C

q = 279.45 cal

So, the heat lost by the metal is 279.45 cal.


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4 years ago
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An orbital is a region of space where there is a high probability of finding an electron.

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The physical property you measured is the boiling point of the liquid.

Therfore, if the liquid has a boiling point of 100°C, it turns from liquid state to vapor when you heat it up to 100°C.

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