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devlian [24]
2 years ago
7

In the preparatory reaction which involves moving pyruvic acid into the mitochondrion

Chemistry
1 answer:
eduard2 years ago
8 0
In the preparatory reaction that involves movement of pyruvic acid into mitochondria TAKES PLACE IN THE MITOCHONDRIAL MATRIX WHERE THE PYRUVIC ACID IS OXIDIZED AND CARBON DIOXIDE IS RELEASED. In this reaction, NAD+ is also reduced. The end products of a preparatory reaction are 4 NADH molecules, 4 hydrogen ions,  2 carbon dioxide molecules, 2 ATP molecules and 2 acetyl CoA molecules.
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What do agents such as chemicals, elevated temperatures, ionizing radiation, and viruses have in common?
Leni [432]

Answer:

All of them affect the DNA

Explanation:

Chemicals are compounds that can pass through cell membranes and modificate the DNA, elevated temperatures can denaturalize the cell and therefore damage the DNA, ionizing radiation can pass through cell organelles and reach the nucleus affecting the DNA, and viruses inject its DNA into the genome and modify it.

4 0
3 years ago
Polonium -210 decays once before it becomes a stable atom. What is that stable atom?
ycow [4]

Answer:

A. 206 Pb

82

Explanation:

5 0
3 years ago
What’s the reaction type of aqueous magnesium sulfate + aqueous sodium carbonate?
IrinaK [193]

Answer: Double displacement reaction

Explanation:

Double displacement reaction is defined as the reaction where exchange of ions takes place.

The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

The chemical reaction between aqueous magnesium sulfate and aqueous sodium carbonate is represented as:

MgSO_4(aq)+Na_2CO_3(aq)\rightarrow Na_2SO_4(aq)+MgCO_3(s)

8 0
2 years ago
How many milliliters of water at 25.0°C with a density of 0.997 g/mL must be mixed with 163 mL of coffee at 97.9°C so that the r
Stolb23 [73]

Answer:

248 mL

Explanation:

According to the law of conservation of energy, the sum of the heat absorbed by water (Qw) and the heat released by the coffee (Qc) is zero.

Qw + Qc = 0

Qw = -Qc [1]

We can calculate each heat using the following expression.

Q = c × m × ΔT

where,

  • c: specific heat
  • m: mass
  • ΔT: change in the temperature

163 mL of coffee with a density of 0.997 g/mL have a mass of:

163 mL × 0.997 g/mL = 163 g

From [1]

Qw = -Qc

cw × mw × ΔTw = -cc × mc × ΔTc

mw × ΔTw = -mc × ΔTc

mw × (54.0°C-25.0°C) = -163 g × (54.0°C-97.9°C)

mw × 29.0°C = 163 g × 43.9°C

mw = 247 g

The volume corresponding to 247 g of water is:

247 g × (1 mL/0.997 g) = 248 mL

8 0
3 years ago
Convert these temperatures to Celsius:<br><br> a. 303 K<br><br> d. 45 K
andre [41]

303K − 273.15 = 29.85°C

45K − 273.15 = -228.1°C

8 0
1 year ago
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