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AnnZ [28]
4 years ago
10

You are working with a concentrated solution of ammonium hydroxide which place of safety equipment is most important to have on

hand
Chemistry
2 answers:
maria [59]4 years ago
5 0
Lab coat, eye protection and gloves
natita [175]4 years ago
3 0
I would say safety goggles
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An acorn with a mass of .0300 kilograms is hanging from a branch in a tree. It is 2.50 meters from the ground. What is the poten
lorasvet [3.4K]
The answer is the first one. Hope this helps!!!!
6 0
4 years ago
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The _____ is the organelle that recycles unneeded molecules
Aneli [31]

Answer: Lysosomes

Explanation: The lysosome is an organelle that contains digestive enzymes and acts as the organelle-recycling facility of an animal cell. It breaks down old and unnecessary structures so their molecules can be reused. Lysosomes are part of the endomembrane system, and some vesicles that leave the Golgi are bound for the lysosome.

4 0
4 years ago
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A sample of nitrosyl bromide (nobr) decomposes according to the equation 2nobr(g)⇌2no(g)+br2(g) an equilibrium mixture in a 5.00
Alex73 [517]

Answer:

Kc = 0.122.

Explanation:

  • We can calculate Kc from the relation: Kc = [NO]².[Br₂] / [NOBr]².
  • Firstly, we convert the number of grams of each component to moles using <em>(n = mass / molar mass)</em>.
  • n of NOBr = (3.26 g / 109.8 g/mole) = 0.03 moles.
  • n of NO = (3.06 g / 29.9 g/mole) = 0.102 moles.
  • n of Br₂ = (8.15 g / 159.9 g/mole) = 0.051 moles.
  • Then we can get the concentration of each component by dividing its no. of moles by the volume of the vessel <em>(concentration = n / V)</em>.
  • The concentration of NOBr = (0.03 mole / 5.00 L) = 6x10⁻³ mol/L.
  • The concentration of NO = (0.102 mole / 5.00 L) = 2x10⁻² mol/L.
  • The concentration of Br₂ = (0.051 mole / 5.00 L) = 1x10⁻² mol/L.
  • Now, we can get Kc:
  • Kc = [NO]².[Br₂] / [NOBr]² = (2x10⁻² mol/L)².(1x10⁻² mol/L) / (6x10⁻³ mol/L)² = 0.122.
7 0
4 years ago
A sample of gas is placed into an enclosed cylinder and fitted with a movable piston. Calculate the work (in joules) done by the
irga5000 [103]

Answer:

The work is -6,497.54 J

Explanation:

Work is the amount of energy transferred from one system to another by a force when a displacement occurs.

The work exchanged for a gas depends on the transformation it performs to go from the initial state to the final state.

The pressure - volume work done by a system that compresses or expands at constant pressure is given by the expression:

W= -P*ΔV

where

  • W is the work exchanged by the system with the environment. Its unit of measure in the International System is the joule (J), which is equivalent to  Pa*m³
  • P: Pressure. Its unit of measurement in the International System is the pascal (Pa).
  • ∆V: Volume variation (∆V = Vfinal - Vinitial). Its unit of measurement in the International System is cubic meter (m³)

In this case:

  • Wsystem=?
  • P= 5.63 atm=570,459.8 Pa (being 1 atm=101325 Pa)
  • ΔV=Vfinal - Vinitial= 15.61 L - 4.22 L= 11.39 L= 0.01139 m³ (being 1 L=0.001 m³)

Replacing:

W=  -570,459.8 Pa*0.01139 m³

Solving:

W=-6,497.54 J

<u><em>The work is -6,497.54 J</em></u>

6 0
3 years ago
Identify the product formed from the phosphorylation of adp.
yulyashka [42]
Phosphorylation is a process in which addition of phosphoryl group is added. This process explains the presence of the PO₃⁻ in the molecules. One type of phosphorylation is that which is termed as the substrate-level phosphorylation. This is a metabolic reaction that allows or results to the formation of ATP due to the direct transfer of phosphoryl to ADP. 

Hence, the answer is ATP. 
4 0
3 years ago
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