Answer:
26 yards
Step-by-step explanation:
The complete question is attached in the image below.
The distance between two points O(
) and P(
) is:
![|OP|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=%7COP%7C%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
The location of the points of the polygon are as follows:
A(-5, 5), B(0. 5), C(4,2), D(1, -2), E(-2, -2), F(-5, 2). Therefore:
![|AB|=\sqrt{(0-(-5))^2+(5-5)^2}=5\ yards \\\\|BC|=\sqrt{(4-0)^2+(2-5)^2}=5\ yards \\\\|CD|=\sqrt{(1-4)^2+(-2-2)^2}=5\ yards \\\\|DE|=\sqrt{(-2-1)^2+(-2-(-2))^2}=3\ yards\\ \\|EF|=\sqrt{(-5-(-2))^2+(2-(-2))^2}=5\ yards \\\\|FA|=\sqrt{(-5-(-5))^2+(2-5)^2}=3\ yards](https://tex.z-dn.net/?f=%7CAB%7C%3D%5Csqrt%7B%280-%28-5%29%29%5E2%2B%285-5%29%5E2%7D%3D5%5C%20yards%20%5C%5C%5C%5C%7CBC%7C%3D%5Csqrt%7B%284-0%29%5E2%2B%282-5%29%5E2%7D%3D5%5C%20yards%20%5C%5C%5C%5C%7CCD%7C%3D%5Csqrt%7B%281-4%29%5E2%2B%28-2-2%29%5E2%7D%3D5%5C%20yards%20%5C%5C%5C%5C%7CDE%7C%3D%5Csqrt%7B%28-2-1%29%5E2%2B%28-2-%28-2%29%29%5E2%7D%3D3%5C%20yards%5C%5C%20%5C%5C%7CEF%7C%3D%5Csqrt%7B%28-5-%28-2%29%29%5E2%2B%282-%28-2%29%29%5E2%7D%3D5%5C%20yards%20%5C%5C%5C%5C%7CFA%7C%3D%5Csqrt%7B%28-5-%28-5%29%29%5E2%2B%282-5%29%5E2%7D%3D3%5C%20yards)
The perimeter of the fence = |AB| + |BC| + |CD| + |DE| + |EF| + |FA| = 5 + 5 + 5 + 3 + 5 + 3 = 26 yards.