Answer:
The original dimensions of the piece of metal are
Length: 36 inches
Width: 21 inches
Step-by-step explanation:
Let
x ----> the original length pf the piece of metal
y ----> the original width pf the piece of metal
we know that
----> equation A
The volume of the box is equal to

we have



substitute in the formula of volume
----> equation B
substitute equation A in equation B

solve for y


Solve the quadratic equation by graphing
using a graphing tool
The solution is y=21
Find the value of x

therefore
The original dimensions of the piece of metal are
Length: 36 inches
Width: 21 inches
f(x) -g(x) = -3x-5 -(4x-2)
distribute
-3x-5 -4x+2
combine like terms
-7x-3
Answer:
-7x-3
Answer: She is incorrect because 0 + 0 = <u>0</u>
A) $15 ÷ 40% =
15×.4= 6
15+6= 21
B) $38 × .25=9.5
38-9.5=28.50
28.50×.06=1.71
28.50+1.17=30.21
I think this is how you do it. would wait for other answers as well to double check.
Answer:
4
Step-by-step explanation: