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lesya692 [45]
3 years ago
6

Sample X has a mass of 22.7 g and reacts with sample Y to form sample XY with a total mass of 86.9 g. What is the mass of sample

Y?
Chemistry
1 answer:
kolezko [41]3 years ago
8 0

Answer:

\large \boxed{\text{64.2 g}}

Explanation:

                 X  +  Y ⟶ XY

mass:  22.7 g   x     86.9 g

According to the Law of Conservation of Mass, the mass of the product must equal the mass of the reactants.

\begin{array}{rcl}\text{22.7 g} + x & = & \text{86.9 g}\\x & = & \text{86.9 g} - \text{22.7 g}\\& = & \textbf{64.2 g}\\\end{array}\\\text{The mass of Y is $\large \boxed{\textbf{64.2 g}}$}

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How much energy is evolved during the reaction of 51.2 g of al, according to the reaction below? assume that there is excess fe2
sesenic [268]

Answer : The amount of energy evolved during the reaction is, -807.696KJ.

Solution : Given,

\Delta H=-852KJ

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Molar mass of Al = 27 g/mole

First we have to calculate the moles of Al.

\text{ Moles of Al}=\frac{\text{ Mass of Al}}{\text{ Molar mass of Al}}=\frac{51.2g}{27g/mole}=1.896moles

The balanced combustion reaction is,

Fe_2O_3+2Al\rightarrow Al_2O_3+2Fe

From the given reaction, we conclude that

As, 2 moles of Al evolved energy = -852KJ

So, 1.896 moles of Al evolved energy = \frac{-852KJ}{2moles}\times 1.896moles=-807.696KJ

Therefore, the amount of energy evolved during the reaction is, -807.696KJ.

8 0
3 years ago
Welding is an industrial process that is used to join pieces of metal. A certain mixture of gases used in welding is composed of
GarryVolchara [31]

The given question is incomplete. The complete question is :

Welding is an industrial process that is used to join pieces of metal. A certain mixture of gases used in welding is composed of carbon dioxide and argon. The partial pressure of carbon dioxide is 0.080 atm and the partial pressure of argon is 0.24 atm. What is the total pressure of the mixture.

Answer:  0.32 atm

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_{CO_2}+p_{Ar}

Given : p_{total} =total pressure of gases = ?

p_{CO_2} = partial pressure of carbon dioxide = 0.080 atm

p_{Ar} = partial pressure of argon = 0.24 atm    

putting in the values we get:

p_{total}=0.080atm+0.24atm  

p_{total}=0.32atm

Thus the total pressure of the gases is 0.32 atm

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3 years ago
A 100. 0 ml sample of 0. 10 m nh3 is titrated with 0. 10 m hno3. Determine the ph of the solution after the addition of 100. 0 m
DerKrebs [107]

The pH of the solution after the addition of 100. 0 ml of HNO3. The kb of NH3 is 1. 8 × 10-5. So, pH is 10.9 basic .

This neutralization occurs as the acid is added to the base:

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The initial moles of NH3present is given by,

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The number of moles of

HNO3 added is given by:

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It is clear from the equation that the acid and base react in a 1:1 molar ratio. So, the no. moles of NH3remaining will be 0.01 - 0.001= 0.009

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At 25∘xC, we know that, pH+ pOH=14

pH= 14− 3.056= 10.9

To know more about Equilbrium, visit-brainly.com/question/14366127

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Answer:

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